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JulijaS [17]
3 years ago
10

Compared with the Earth's atmosphere, the atmosphere of Venus is much _______, has a greater percentage of CO2, and has a ______

_ greenhouse effect. A. thicker; stronger B. thinner; stronger C. thicker; weaker D. thinner; weaker
Physics
1 answer:
wolverine [178]3 years ago
8 0
1.A thicker stronger
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The answer is 2400 centimeters
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A 4.9-MeV (kinetic energy) proton enters a 0.28-T field, in a plane perpendicular to the field. Part APart complete What is the
BartSMP [9]

Answer:

r=1.14m

Explanation:

\theta is the angle between the velocity and the magnetic field. So, the magnetic force on the proton is:

F_m=qvBsen\theta\\F_m=qvBsen(90^\circ)\\F_m=qvB

A charged particle describes a semicircle in a uniform magnetic field. Therefore, applying Newton's second law to uniform circular motion:

F_m=F_c\\qvB=F_c(1)

F_c is the centripetal force and is defined as:

F_c=m\frac{v^2}{r}

Here v is the proton's speed and r is the radius of the circular motion. Replacing this in (1) and solving for r:

qvB=\frac{mv^2}{r}\\r=\frac{mv^2}{qvB}\\r=\frac{mv}{qB}

Recall that 1 J is equal to 6.242*10^{12}MeV, so:

4.9MeV*\frac{1J}{6.242*10^{12}MeV}=7.85*10^{-13}J

We can calculate v from the kinetic energy of the proton:

K=\frac{mv^2}{2}\\\\v=\sqrt{\frac{2K}{m}}\\v=\sqrt{\frac{2(7.85*10^{-13}J)}{1.67*10^{-27}kg}}\\v=3.06*10^{7}\frac{m}{s}

Finally, we calculate the radius of the proton path:

r=\frac{mv}{qB}\\r=\frac{1.67*10^{-27}kg(3.06*10^{7}\frac{m}{s})}{1.6*10^{-19}C(0.28T)}\\r=1.14m

8 0
3 years ago
For a given wave if the frequency doubles the wave length?
pav-90 [236]
For a given wave in a given medium, if the frequency doubles,
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Answer:

that is going at a constant rate

Explanation:

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Two books that changed the science of astronomy and the world were_____by Nicholas Copernicus and_____by Isaac Newton.
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Hope my answer would be a great help for you.    
If you have more questions feel free to ask here at Brainly.  
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