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JulijaS [17]
3 years ago
10

Compared with the Earth's atmosphere, the atmosphere of Venus is much _______, has a greater percentage of CO2, and has a ______

_ greenhouse effect. A. thicker; stronger B. thinner; stronger C. thicker; weaker D. thinner; weaker
Physics
1 answer:
wolverine [178]3 years ago
8 0
1.A thicker stronger
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A student conducts an experiment in which a cart is pulled by a variable applied force during a 2sec time interval. In trial 1,
Harlamova29_29 [7]

Answer:

change of momentum does not depend on the mass of the cars, as the force and time are the same all vehicles have the same change of momentum

Explanation:

Let's look for the speed of the car

     F = m a

    a = F / m

We use kinematics to find lips

    v = v₀ + a t

    v = v₀ + (F / m) t

The moment is defined by

    p = m v

The moment change

    Δp = m v - m v₀

Let's replace the speeds in this equation

    Δp = m (v₀ + F / m t) - m v₀

    Δp = m v₀  + F t - m v₀  

    Δp = F t

We see that the change of momentum does not depend on the mass of the cars, as the force and time are the same all vehicles have the same change of momentum

8 0
3 years ago
An airplane is being pushed West by its engines with a force of 350 N as it starts to take off the runway at the Atlanta airport
Marizza181 [45]

Answer:

option C

Explanation:

given,

Force by the engine on plane in West direction = 350 N

Frictional force on the runway = 100 N in east

force exerted by the wind = 100 N in east

net force and direction = ?

consider west to be positive and east be negative.

when airplane will be moving there will be frictional as well as wind resistance will be acting in opposite direction of airplane

Net force = 350 N - 100 N - 100 N

                 = 150 N

as our answer comes out to be positive so the airplane will be moving in West

hence, the correct answer is option C

8 0
3 years ago
What is the chemical name for lime
Sergio039 [100]
Calcium Oxide
CaO I think
5 0
3 years ago
A 4.0-cm tall light bulb is placed at distance of 8.3 cm from a concave mirror having a focal length of 15.2 cm. Determine the i
scoundrel [369]

Answer: the image distance is -18, 28 cm this means behind of the concave mirror. The image size is 2.2 higher that the original  so it has 8.8 cm with the same orientation as original  and it is a virtual imagen.

Explanation: In order to sove the imagen formation for a concave mirror we have to use the following equation:

1/p+1/q=1/f  where p and q represents the distance to the mirror  for the object and imagen, respectively. f is the focal length for the concave mirror.

replacing the values we obtain:

1/8.3+1/q=1/15.2

so 1/q=(1/15.2)-(1/8.3)=-54.7*10^-3

then q=-18.28 cm

The magnification is given by M=-q/p=-(-18,28)/8.3= 2.2

We also add a picture to see the imagen formation for this case.

6 0
3 years ago
A particular conductor has 3.0 × 10^27 mobile electrons per cubic meter. The material is in the shape of a cylinder of length 6.
irina1246 [14]

Answer:

Explanation:

Given

Length of cylinder L=6 cm

diameter of cylinder d=1 cm

Area of cross-section A=\frac{\pi\times d^2}{4}

A=\frac{\pi \times 10^{-4}}{4}=7.855\times 10^{-5} m^2

Emf =2.5 V

current I=5 mA

Resistance=\frac{V}{I}=\frac{2.5}{5\times 10^{-3}}

R=500 \Omega

R is also given by

R=\rho \frac{L}{A}

where \rho =resistivity

\rho =\frac{RA}{L}=\frac{500\times 7.85\times 10^{-3}}{6}

\rho =0.654 \Omega -m        

6 0
3 years ago
Read 2 more answers
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