The gas tank of Dave’s car has a capacity of 12 gallons. The tank was 38 full before Dave filled it to capacity. It cost him $2.
2 answers:
Answer:
$ 18.75
Explanation:
given,
capacity of the Dave’s car = 12 gallons
Assuming that the tank is 3/8 full before
Cost of gas per gallon = $2.50 per gallon of gas
Volume Dave have to fill
=
= of full tank
=
volume Dave have to fill = 7.5 gallons
total money Dave spent
= 7.5 gallons x $2.50
= $ 18.75
Dave have to spend $ 18.75 to fill tank to it capacity.
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Answer:
<em>The power required by the pump is nearly 230.588 kW</em>
Explanation:
Flow rate of the pump Q = 1 m^3/s
the head flow H = 20 m
specific weight of water γ = 9800 N/m^3
efficiency of the pump η = 85%
First note that specific gravity of water is the product of the density of water and acceleration due to gravity.
γ = ρg
where ρ is density. For water its value is 1000 kg/m^3
g is the acceleration due to gravity = 9.81 m/s^2
The power to lift this water at this rate will be gotten from the equation
P = ρgQH
but ρg = γ
therefore,
P = γQH
imputing values, we'll have
P = 9800 x 1 x 20 = 196000 W
But the centrifugal pump that will be used will only be able to lift this amount of water after the efficiency factor has been considered. The power of pump needed must be greater than this power.
we can say that
196000 W is 85% of the power of the pump power needed, therefore
196000 = 85% of
where is the power of the pump needed
85% = 0.85
196000 = 0.85
= 196000/0.85 = 230588.24 W
<em>Pump power = 230.588 kW</em>