Answer:
a) V1=11.05m/s V2=92.07m/s V3=17.24m/s
b) KE = 16238.26J
Explanation:
For tangential speeds:
For the kinetic energy, it can be calculated as:
Where:
So,
KE=16238.26J
1). Work = (force) x (distance)
Work = (3,000 newtons) x (35 meters) = 105,000 newton-meters = <em>105,000 joules</em>
2). Power = (work) / (time)
Power = (105,000 joules) / (90 seconds)
= 1,166-2/3 joules per second =<em> 1,166 and 2/3 watts</em> .
<em>Note:</em>
That's no ordinary man.
1,166 watts is the same as roughly 1.6 horsepower.
Not too many people can sustain 1 horsepower or more for 90 seconds.
Answer:
3.834 m/s
Explanation:
h = 0.750 m
vx = 5 m/s
Let the initial vertical velocity is vy.
Final vertical velocity is zero
use third equation of motion along y axis
v^2 = vy^2 - 2 x g x h
0 = vy^2 - 2 x 9.8 x 0.75
vy^2 = 14.7
vy = 3.834 m/s
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