The magnitude of the vertical force that a concrete support exerts on the bridge at the far end is 201.25 N.
<h3>What is force?</h3>
The force is an action of push or pull which makes a body to move or stop.
Given is the weight of tourist W = 805 N and L is the length of the bridge.
Let the reaction force at both the ends of the bridge is R1 and R2.
Taking the moments about point A,
R1 x 0 - W x L/4 +R2 x L =0
R2 = W/4
R2 = 805 /4
R2 = 201.25 N
Thus, the magnitude of the vertical force that a concrete support exerts on the bridge at the far end is 201.25 N.
Learn more about force.
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Complete Question
The
Answer:
a
![E_r = 3.058 \ J](https://tex.z-dn.net/?f=E_r%20%3D%20%203.058%20%5C%20J)
b
![E_b = -11.466 \ J](https://tex.z-dn.net/?f=E_b%20%20%3D%20%20-11.466%20%5C%20J)
c
![\Delta E_n = -14.524 \ J](https://tex.z-dn.net/?f=%5CDelta%20E_n%20%3D%20-14.524%20%5C%20J)
Explanation:
From the question we are told that
The mass of the stone is ![m_s = 0.26 \ kg](https://tex.z-dn.net/?f=m_s%20%20%3D%20%200.26%20%5C%20kg)
The height above the top of the water is ![h = 1.2 \ m](https://tex.z-dn.net/?f=h%20%3D%201.2%20%5C%20m)
The depth of the well is ![d = 4.5 \ m](https://tex.z-dn.net/?f=d%20%3D%20%204.5%20%5C%20m)
The gravitational potential of the stone before it was released is
![E_r = mgh](https://tex.z-dn.net/?f=E_r%20%3D%20%20mgh)
substituting values
![E_r = 0.26 * 9.8 * 1.2](https://tex.z-dn.net/?f=E_r%20%3D%20%200.26%20%2A%20%209.8%20%2A%20%201.2)
![E_r = 3.058 \ J](https://tex.z-dn.net/?f=E_r%20%3D%20%203.058%20%5C%20J)
The gravitation potential of the stone when it reaches the bottom of the well is
![E_b = mg(- d)](https://tex.z-dn.net/?f=E_b%20%20%3D%20%20mg%28-%20d%29)
The negative shows that the potential energy of the stone as compared to the earth is reducing
substituting values
![E_b = 0.26 * 9.8 *(- 4.5)](https://tex.z-dn.net/?f=E_b%20%20%3D%20%200.26%20%2A%209.8%20%2A%28-%204.5%29)
![E_b = -11.466 \ J](https://tex.z-dn.net/?f=E_b%20%20%3D%20%20-11.466%20%5C%20J)
The change in the systems gravitational potential is
![\Delta E_n = E_b - E_r](https://tex.z-dn.net/?f=%5CDelta%20E_n%20%3D%20%20E_b%20-%20E_r)
substituting values
![\Delta E_n = -11.466 - 3.058](https://tex.z-dn.net/?f=%5CDelta%20E_n%20%3D%20%20-11.466%20-%203.058)
![\Delta E_n = -14.524 \ J](https://tex.z-dn.net/?f=%5CDelta%20E_n%20%3D%20-14.524%20%5C%20J)
<h2>Answer:</h2>
Phytochemicals are compounds that are produced by plants ("phyto" means "plant"). They are found in fruits, vegetables, grains, beans, and other plants. Some of these phytochemicals are believed to protect cells from damage that could lead to cancer.
Answer:
Explanation:
Let the highest and lowest score be a and b respectively .
a - b = 10
a = 10 + b
The numbers in descending order are a , 98 , 98 , b .
mean = 100 , so
4 x 100 = a + 98 + 98 + b = 10 + b + 98 + 98 + b = 206 + 2b
400 = 206 + 2b
2b = 194
b = 97
a = 107
So the scores were as follows
107 , 98 , 98 , 97
Answer:
![K_r = \frac{K}{2}](https://tex.z-dn.net/?f=K_r%20%3D%20%5Cfrac%7BK%7D%7B2%7D)
so kinetic energy of the drum is half the kinetic energy of the particle
Explanation:
Here we know that the particle is connected with the drum through a string
So here we can say that velocity of the particle is same as the tangential velocity of the drum as the particle is connected with the string which is wounded on the drum
So here we can say
![v = r\omega](https://tex.z-dn.net/?f=v%20%3D%20r%5Comega)
now kinetic energy of the particle is given as
![K = \frac{1}{2}mv^2](https://tex.z-dn.net/?f=K%20%3D%20%5Cfrac%7B1%7D%7B2%7Dmv%5E2)
at the same time the rotational kinetic energy of the drum is given as
![K_r = \frac{1}{2}I\omega^2](https://tex.z-dn.net/?f=K_r%20%3D%20%5Cfrac%7B1%7D%7B2%7DI%5Comega%5E2)
![K_r = \frac{1}{2}(\frac{1}{2}mR^2)(\frac{v^2}{R^2})](https://tex.z-dn.net/?f=K_r%20%3D%20%5Cfrac%7B1%7D%7B2%7D%28%5Cfrac%7B1%7D%7B2%7DmR%5E2%29%28%5Cfrac%7Bv%5E2%7D%7BR%5E2%7D%29)
![K_r = \frac{1}{4}mv^2](https://tex.z-dn.net/?f=K_r%20%3D%20%5Cfrac%7B1%7D%7B4%7Dmv%5E2)
![K_r = \frac{K}{2}](https://tex.z-dn.net/?f=K_r%20%3D%20%5Cfrac%7BK%7D%7B2%7D)
so kinetic energy of the drum is half the kinetic energy of the particle