The car will take 300 m before it stops due to applying break.
<h3>What's the relation between initial velocity, final velocity, acceleration and distance?</h3>
- As per Newton's equation of motion, V² - U² = 2aS
- V= final velocity velocity of the object, U = initial velocity velocity of the object, a= acceleration, S = distance covered by the object
- Here, U = 60 ft/sec, V = 0 m/s, a= -6 ft/sec²
- So, 0² - 60² = 2×6× S
=> -3600 = -12S
=> S = 3600/12 = 300 m
Thus, we can conclude that the distance covered by the car is 300 m before it stopped.
Disclaimer: The question was given incomplete on the portal. Here is the complete question.
Question: A car is being driven at a rate of 60 ft/sec when the brakes are applied. The car decelerates at a constant rate of 6 ft/sec². How long will it take before the car stops?
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Answer:
<h2>50 J</h2>
Explanation:
The kinetic energy of an object can be found by using the formula
m is the mass
v is the velocity
From the question we have
We have the final answer as
<h3>50 J</h3>
Hope this helps you
Answer: U = 120 m/s
v = 0
t = 0.01 s
a = (v-u)/ t = -120 / 0.01 = -12000 m/s
a) S = (v² - u²)/2a = -120² / 2*(-12000) = 120 / 200 = 0.6 m
distance of penetration is 0.6m
b) force = ma = 0.005×12000 = 60N
Solution:
Given:
initial orbit of electron=
final orbit of electron=
to find wavelength we use Rydberg equation:
1/λ
where R is Rydberg constant and it's value is
inserting all the values in formula
1/λ
λ
for it's region and color look at given attached pictures