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3 years ago

10

What is the minimum value for h(x)=x2−16x+60?

1 answer:

Mila [183]3 years ago

7 0

Minimum value is equal to x=8, y=-4First find the derivative of the original equation which equals= d/dx(x^2-16x+60) = 2x - 16at x=8, f'(x), the derivative of x equals zero, so therefore, at point x = 8, we have a minimum value.Just plug in 8 to the original equation to find the answer for the minimum value.

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3 years ago

The length of the line segment containing the points (1,7) and (5,5)

ArbitrLikvidat [17]

Answer:

True

Step-by-step explanation:

Let A denotes the point (1,7)

Let B denotes the point (5,5)

We are supposed to find The length of the line segment containing the points

Formula : $d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$(x_1,y_1)=(1,7)\\(x_2,y_2)=(5,5)\\ d = \sqrt{(5-1)^2+(5-7)^2}\\ d = \sqrt{4^2+(-2)^2}\\ d = \sqrt{4^2+(-2)^2}\\d=4.47$

So,The length of the line segment containing the points (1,7) and (5,5) is 4.47 units is true.

Hence Option A is true

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