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2 years ago

11

What is the total enthalpy change for the reaction? Is the reaction exothermic or endothermic?

1 answer:

Nuetrik [128]2 years ago

8 0

Answer: S8(s) + 8O2(g) → 8SO2(g) ΔH = -2368 kJ a.

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How are elements in each group the same?

Amanda [17]

Answer:

They share the same number of electrons in their valence subshells.

Explanation:

They have the same number of electrons on the outer shell.

6 0

2 years ago

Scientific explanations

Sergio039 [100]

I think that it's cannot include supernatural explanations, or C.

If i got it wrong sorry

6 0

3 years ago

A 32.2 g iron rod, initially at 21.9 C, is submerged into an unknown mass of water at 63.5 C. in an insulated container. The fin

lorasvet [3.4K]

Answer : The mass of the water in two significant figures is, $3.0\times 10^1g$

Explanation :

In this case the heat given by the hot body is equal to the heat taken by the cold body.

$q_1=-q_2$

$m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)$

where,

$c_1$ = specific heat of iron metal = $0.45J/g^oC$

$c_2$ = specific heat of water = $4.18J/g^oC$

$m_1$ = mass of iron metal = 32.3 g

$m_2$ = mass of water = ?

$T_f$ = final temperature of mixture = $59.2^oC$

$T_1$ = initial temperature of iron metal = $21.9^oC$

$T_2$ = initial temperature of water = $63.5^oC$

Now put all the given values in the above formula, we get

$32.3g\times 0.45J/g^oC\times (59.2-21.9)^oC=-m_2\times 4.18J/g^oC\times (59.2-63.5)^oC$

$m_2=30.16g\approx 3.0\times 10^1g$

Therefore, the mass of the water in two significant figures is, $3.0\times 10^1g$

3 0

2 years ago

Which of the following is an example of behavioral variation?

ANTONII [103]

Answer: A, parrots eat seeds, fruit, and nuts, while hawks eat meat.

Explanation:

This option is more onto the behavioral and what the parrots did, while the other options were more on the parrots physical attributions.

<em>I hope this helped! :)</em>

5 0

3 years ago

HRISTINA HERRERA: Attempt 1

Lunna [17]

Answer:

7.5 g of hydrogen gas reacts with 50.0 g oxygen gas to form 57.5 g of water.

Explanation:

Here we have the check if the mass of the reactants is equal to the mass of the products.

Reactants

$7.5+50=57.5\ \text{g}$

Products

$57.5\ \text{g}$

The data is consistent with the law of conservation of matter.

Reactants

$50+243=293\ \text{g}$

Products

$206+97=303\ \text{g}$

The data is not consistent with the law of conservation of matter.

Reactant

$17.7+34.7=52.4\ \text{g}$

Products

$62.4\ \text{g}$

The data is not consistent with the law of conservation of matter.

Only the first data is consistent with the law of conservation of matter.

8 0

2 years ago