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DedPeter [7]
3 years ago
15

Convert methane into ethane

Chemistry
1 answer:
Gwar [14]3 years ago
6 0
Remove the independent variable m
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A solution of Na2CO3 is added dropwise to a solution that contains 1.15×10−2 M Fe2+ and 0.58×10−2 M Cd2+. What concentration of
castortr0y [4]

The question is incomplete, complete question is;

A solution of Na_2CO_3 is added dropwise to a solution that contains1.15\times 10^{-2} M of Fe^{2+} and 0.58\times 10^{-2} M and Cd^{2+}.

What concentration of CO_3^{2-} is need to initiate precipitation? Neglect any volume changes during the addition.

K_{sp} value FeCO_3: 2.10\times 10^{-11}

K_{sp} value CdCO_3: 1.80\times 10^{-14}

What concentration of CO_3^{2-} is need to initiate precipitation of the first ion.

Answer:

Cadmium carbonate will precipitate out first.

Concentration of CO_3^{2-} is need to initiate precipitation of the cadmium (II) ion is 3.103\times 10^{-12} M.

Explanation:

1) FeCO_3\rightleftharpoons Fe^{2+}+CO_3^{2-}

The expression of an solubility product of iron(II) carbonate :

K_{sp}=[Fe^{2+}][CO_3^{2-}]

2.10\times 10^{-11}=0.58\times 10^{-2} M\times [CO_3^{2-}]

[CO_3^{2-}]=\frac{2.10\times 10^{-11}}{1.15\times 10^{-2} M}

[CO_3^{2-}]=1.826\times 10^{-9}M

2) CdCO_3\rightleftharpoons Cd^{2+}+CO_3^{2-}

The expression of an solubility product of cadmium(II) carbonate :

K_{sp}=[Cd^{2+}][CO_3^{2-}]

1.80\times 10^{-14}=0.58\times 10^{-2} M\times [CO_3^{2-}]

[CO_3^{2-}]=\frac{1.80\times 10^{-14}}{0.58\times 10^{-2} M}

[CO_3^{2-}]=3.103\times 10^{-12} M

On comparing the concentrations of carbonate ions for both metallic ions, we can see that concentration to precipitate out the cadmium (II) carbonate from the solution is less than concentration to precipitate out the iron (II) carbonate from the solution.

So, cadmium carbonate will precipitate out first.

And the concentration of carbonate ions to start the precipitation of cadmium carbonate we will need concentration of carbonate ions greater than the 3.103\times 10^{-12} M concentration.

6 0
3 years ago
Compare the viscosity property of solid and liquid. ​
Nitella [24]

Answer

There is nothing like viscosity in solid because most of the solids usually have a rigid body. This is due to strong intermolecular forces. And it is due to this strong force between the molecules that they are unable to move and they remain fixed at their position. Some solids such as graphite which have layered structure, don't possess the property of viscosity, because of the strong force between the layers.

Explanation:

Viscosity is the property of a fluid that opposes the relative motion between two surfaces of the fluid that are moving at different velocities. In simple terms, viscosity means friction between the molecules of fluid.

FOR EXAMPLE

water is "thin", having a low viscosity, while vegetable oil is "thick" having a high viscosity

7 0
2 years ago
What is the biggest difference between thermal energy and temperature?
Oliga [24]

Answer:

Heat deals more with thermal energy whereas temperature deals with molecular kinetic energy.

7 0
3 years ago
375 mL of a 0.88 M potassium hydroxide solution is added to 496 mL of a 0.76 M cesium hydroxide solution. Calculate the pOH of t
AysviL [449]

Answer:

pOH of resulting solution is 0.086

Explanation:

KOH and CsOH are monoacidic strong base

Number of moles of OH^{-} in 375 mL of 0.88 M of KOH = \frac{0.88\times 375}{1000}moles = 0.33 moles

Number of moles of OH^{-} in 496 mL of 0.76 M of CsOH = \frac{0.76\times 496}{1000}moles = 0.38 moles

Total volume of mixture = (375 + 496) mL = 871 mL

Total number of moles of OH^{-} in mixture = (0.33 + 0.38) moles = 0.71 moles

So, concentration of OH^{-} in mixture, [OH^{-}] = \frac{0.71}{871}\times 1000M=0.82M

Hence, pOH=-log[OH^{-}]=-log(0.82)=0.086

8 0
2 years ago
dentify the correct formula for the following ionic compounds. - sodium chloride - magnesium chloride - calcium oxide - lithium
andrey2020 [161]

Explanation:

The chemical formula of an ionic compound can be written by using the symbols of the respective cations and anions.

The overall charge on the molecule should be zero.

Hence, the total charge of cations=total charge of anions.

The symbols of the given molecules are shown below:

sodium chloride  ---- NaCl

magnesium chloride ---MgCl_2

calcium oxide ---- CaO

lithium phosphide----Li_3P

aluminum sulfide ----- Al_2S_3

calcium nitride---- Ca_3N_2

5 0
3 years ago
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