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klasskru [66]
3 years ago
5

Plz answer question (ii)

Chemistry
1 answer:
Vanyuwa [196]3 years ago
6 0

Answer:

  1. At the negative electrode: Mg(s) => Mg2+ + 2e-
  2. At the positive electrode:Cl- + 2e- => Cl2(g)

Explanation:

1. Magnesium is formed at the negative electrode.

2. Chlorine gas is released at the positive electrode.

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Calculate the shortest wavelength of light capable of dissociating the Cl–F bond in one molecule of chlorine monofluoride if the
Fofino [41]

Answer:

477 nm

Explanation:

Using the expression for the energy as:

E=\frac {h\times c}{\lambda}

Where,  

h is Plank's constant having value 6.626\times 10^{-34}\ Js

c is the speed of light having value 3\times 10^8\ m/s

\lambda is the wavelength of the light

Given, Energy=251\ kJ/mol=251000\ J/mol

Also, N_a=6.023\times 10^{23}\ {mol}^{-1}

So, Energy for one atom = \frac{251000}{6.023\times 10^{23}}\ J

Thus, applying values as:

\frac{251000}{6.023\times 10^{23}}=\frac{6.626\times 10^{-34}\times 3\times 10^8}{\lambda}

251\times \:10^{26}\lambda=5^{20}\times \:125540965

\lambda=4.77\times 10^{-7}\ m=477\times 10^{-7}\ m=477\ nm

( 1 m = 10^{-9} nm )

8 0
4 years ago
What are two things that you observed when you heated the mixture of tin and nitric acid over the Bunsen burner in the virtual l
Rus_ich [418]
1. The reaction for this would be:

Sn + 4 HNO₃ →  SnO₂ + 4 NO₂ + 2 H₂O

The first observation would be bubbling of the solution and brown acrid smoke is produced due to the presence of NO₂ gas. Another observation would be the presence of a white solid which is SnO₂.

2. Heating was required to get rid of the H₂O. When all moisture is gone, you weigh the sample. Afterwhich, you further heat it to get ride of the oxygen. By doing this, you would know the individual mass of each element. Then, you can solve for the empirical formula of the oxide of tin.
3 0
4 years ago
Calculate the molality 6.75% solution of ethanol in water​
Arlecino [84]

The molality of solution = 1.576

<h3>Further explanation</h3>

Given

6.75% solution of ethanol in water​

Required

The molality

Solution

Assume 100 g solution ,

Ethanol = 6.75 g⇒solute

Water = 93.25 g = 0.09325 kg⇒solvent

<em>Molality = mol solute/kg solvent</em>

mol Ethanol(MW=46 g/mol) :

\tt mol=\dfrac{6.75}{46}=0.147

the molality :

\tt m=\dfrac{0.147}{0.09325}=1.576

8 0
3 years ago
Round the answer for the following question to the correct number of significant figures: 38,736 km ÷ 4784 km
uysha [10]

Answer:

Explanation:

38736 ÷ 4784 = 8.097

Sig Figs

4

8.097

Decimals

3

8.097

Scientific Notation

8.097 × 10^0

E-Notation

8.097e+0

Words

eight point zero nine seven

4 0
3 years ago
Jane Doe has a cholesterol (C27H46O) count of 178 mg/dL. How many cholesterol molecules does Jane Doe have in each deciliter of
Ilya [14]

Answer:

Jane has 2.77 * 10^20 molecules cholesterol in 1 dL of blood

Explanation:

<u>Step 1:</u> Given data

Molar mass of Cholesterol =  386.654 g/mol

Jane has a cholesterol of 178 mg/dL

<u>Step 2:</u> Calculate mass of cholsterol in 1 dL

178 mg/dL means in 1 dL she has 178 mg cholesterol or 0.178 grams

<u>Step 3</u>: Calculate number of moles of cholesterol

Number of moles = mass of cholesterol / molar mass of cholesterol

Number of moles = 0.178 grams / 386.654 g/mol = 4.6 * 10^-4 moles

<u>Step 4: </u>Calculate number of molecules

Number of molecules = 4.6 * 10^-4 mol * 6.022 *10^23 / mol = 2.77 * 10^20 molecules

Jane has 2.77 * 10^20 molecules cholesterol in 1 dL of blood

4 0
3 years ago
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