Question

Calculate the height of a column of carbon tetrachloride, CCl4(l), with a density of 1.59 g/mL that exerts the same pressure as a 15.2 cm column of Mercury, Hg(l), that has a density of 13.6 g/ml. Express your answer in meters.

Answer 1

Answer:

1.30 m

Explanation:

The pressure (P) exerted by a column of a liquid can be calculated with the following expression:

$P=\rho \times g \times h$

where,

ρ is the density of the liquid

g is the gravity

h is the height of the column

If both liquids exert the same pressure:

$PHg = PCCl_{4}\\\rho Hg \times g \times hHg = \rho CCl_{4} \times g \times hCCl_{4}\\\rho Hg \times hHg = \rho CCl_{4} \times hCCl_{4}\\hCCl_{4 = \frac{\rho Hg \times hHg}{\rho CCl_{4}} =\frac{13.6g/mL \times 15.2cm}{1.59g/mL} = 130cm=1.30m$