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3 years ago

Help please I’ll mark brailiest

Mathematics

1 answer:

oksian1 [2.3K]3 years ago

8 0

Answer:

DB,AB,AD,CD,AC

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J1, J2 and J3 are three junctions on a motorway. The distance from J2 to J3 is 8.7 miles. The distance from J1 to J2 is one-thir

leonid [27]

Answer:

11.6 miles

Step-by-step explanation:

Given that:

Distance from J2 to J3 = 8.7 miles

Distance between J1 and J2 = 1/3 of J2 toJ3

Hence, distance between J1 and J2 becomes :

1/3 * 8.7 miles = 2.9 miles

Distance from J1 to J3 equals :

(J1 to J2) + (J2 to J3)

2.9 miles + 8.7 miles

= 11.6 miles

5 0

3 years ago

Write y=-3x^2-18x-31 in vertex form

Ahat [919]

-3(x+(3))^2-4 is the answer

8 0

3 years ago

Read 2 more answers

I need helppp help meeeeeeee

Rama09 [41]

1) $\frac{11-13}{4-7}= \frac{2}{3}$

2) $\frac{-2-7}{-10-(-7)}=\frac{-9}{-3} =3$

3) $\frac{9-3}{-11-(-14)} =\frac{6}{3}=2$

4) $\frac{8-4}{11-(-9)} =\frac{4}{20}= \frac{1}{5}$

ok done. Thank to me :>

8 0

2 years ago

I would appreciate it if you guys pls help me asap !!

nydimaria [60]

Answer:C or B

Step-by-step explanation: im outta school so i really dont remeber but guess.

8 0

3 years ago

Read 2 more answers

I need help with this question

Murrr4er [49]

The number of cows is given by

$14\cdot 2^{\frac{y}{5}}$

So, after $k$ years, the number of cows will be

$14\cdot 2^{\frac{y+k}{5}}$

We want this number to be twice as much as the original:

$14\cdot 2^{\frac{y+k}{5}} = 2(14\cdot 2^{\frac{y}{5}})$

First of all, we can cancel 14 from both sides:

$2^{\frac{y+k}{5}} = 2\cdot 2^{\frac{y}{5}}$

Finally, on the right hand side, we can use the exponent rule

$a^b\cdot a^c=a^{b+c}$

to get

$2^{\frac{y+k}{5}} = 2^{\frac{y}{5}+1}$

To solve this equation, we must impose that the two exponents are the same:

$\dfrac{y+k}{5} = \dfrac{y}{5}+1 \iff \dfrac{y+k}{5} = \dfrac{y+5}{5}$

And clearly this is true if and only if $k=5$ . So, it will take 5 years for the cow heard to double in number.

You can do the exact same steps to find the doubling time for the sheeps.

8 0

3 years ago