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2 years ago

Part A Summarize your research, and describe the attributes of the savanna.

2 answers:

Nutka1998 [239]2 years ago

8 0

Savannas are grasslands found in Africa, Australia, South America, and India. The climate is warm or hot. Savannas experience both dry and rainy seasons. Each year, savannas receive about 20 to 50 inches of rain in a span of six to eight months. The other months are dryer. There’s also a threat of wildfires because of the severe dryness during these months. Grasslands are true to their name because their vegetation is mostly grass. Savannas are home to a wide range of animals, including different species of beetles and insects, which many creatures consume. Squirrels, mice, elephants, gazelles, and antelopes are the plant-eating animals that live in the savanna. Hyenas, lions, and leopards are some of the meat-eating animals in these areas. Some of the nonliving components of the system include very porous soil that allows water to drain easily.

zhuklara [117]2 years ago

7 0

Answer:

Savanna regions have two distinct seasons - a wet season and a dry season. There is very little rain in the dry season. In the wet season vegetation grows, including lush green grasses and wooded areas.

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2 years ago

Calculate the molality of a solution that contains 51.2 g of naphthalene, C10H8, in 500 mL of carbon tetrachloride. The density

PtichkaEL [24]

Answer: The molality of naphthalene solution is 0.499 m

Explanation:

Density is defined as the ratio of mass and volume of a substance.

$\text{Density}=\frac{\text{Mass}}{\text{Volume}}$ ......(1)

Given values:

Volume of carbon tetrachloride = 500 mL

Density of carbon tetrachloride = 1.60 g/mL

Putting values in equation 1, we get:

$\text{Mass of carbon tetrachloride}=(1.60g/mL\times 500mL)=800g$

Molality is defined as the amount of solute expressed in the number of moles present per kilogram of solvent. The units of molarity are mol/kg. The formula used to calculate molarity:

$\text{Molality of solution}=\frac{\text{Given mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Mass of solvent (in g)}}$ .....(2)

Given values:

Given mass of naphthalene = 51.2 g

Molar mass of naphthalene = 128.17 g/mol

Mass of solvent = 800 g

Putting values in equation 2, we get:

$\text{Molality of naphthalene}=\frac{51.2\times 1000}{128.17\times 800}\\\\\text{Molality of naphthalene}=0.499m$

Hence, the molality of naphthalene solution is 0.499 m

4 0

2 years ago

The formation of tert-butanol is described by the following chemical equation: (CH3), CBr (aq) + OH(aq) → Br" (aq) +(CH), COH(aq

Dafna11 [192]

Answer:

$(CH_3)_3С^+ (aq) + OH^- (aq)\rightarrow (CH_3)_3COH (aq)$

Explanation:

There are two ways of looking at this problem. The first way, slightly more advanced, is to understand that the carbocation formed is an intermediate in this reaction: it is formed in one step and consumed in the subsequent step.

Secondly, we have hydroxide involved as our reactant, so it should be our second reactant in the second bimolecular step.

Thirdly, the product formed would be a combination of the anion and cation, one of our products, this means we have the following second step:

$(CH_3)_3С^+ (aq) + OH^- (aq)\rightarrow (CH_3)_3COH (aq)$

Another way is to verify this knowing that by adding all of the steps should yield a net equation, notice if we add the two steps together (reactants on one side and products on the other), we obtain:

$(CH_3)_3С^+ (aq) + OH^- (aq) + (CH_3)_3CBr (aq)\rightarrow (CH_3)_3COH (aq) + (CH_3)_3C^+ (aq) + Br^- (aq)$

Notice that the intermediate carbocation cancels out on both sides to yield the final net equation:

$OH^- (aq) + (CH_3)_3CBr (aq)\rightarrow (CH_3)_3COH (aq) + Br^- (aq)$

This means we have the correct second step.

6 0

3 years ago