Answer:
C) It has a long preganglionic fibers
Explanation:
Peripheral nervous system (PNS) is the nervous system that contains nerves and ganglia outside the central nervous system (CNS). PNS is divided into:
- somatic (voluntary) nervous system-controls the movements of the skeletal muscles
- autonomic (involuntary) nervous system-controls the smooth muscles and glands and thus it is the regulator of the major body functions. It is subdivided into tree groups:
- sympathetic ("fight and flight") system-responsible for stressful and active situations (but also in normal conditions);contains short preganglionic fibers and long postganglionic fibers.
- parasympathetic ("rest and digest") system-opposite to sympathetic, responsible for the maintenance of body's activities at rest.
- enteric nervous system-controls the function of the gastrointestinal tract.
If you could tell me what cell it would be easier. Sorry I have to post it on Answer but I't does not show the commentary or whatever you guys call it.
When crossing alleles for color, you get
25% pp
50% Pp
25% PP
White flowers are recessive, so there is a 1/4 chance
And when crossing alleles for shape you get
25% rr
50% Rr
25% RR
Wrinkled seeds are recessive so there is a 1/4 chance
Since you are looking for white flowers AND wrinkled seeds, you need to multiply 1/4 x 1/4, giving you a 1/16 chance that the offspring will have these two traits
Answer:

Explanation:
It is given that
B is the dominant allele which represents the black color
and b is the recessive allele which represents the white fur.
B being dominant will result into black color fur for genotype "Bb"
Given -
Frequency of black fur allele (p) is 
As per Hardy Weinberg's first law of equilibrium

Substituting the value of p in above equation, we get -

q represents the frequency for white fur allele
Frequency of white fur phenotype is

Frequency of homozygous black fur phenotype (BB) is

As per Hardy Weinberg's second law of equilibrium -

Combined frequency of homozygous and heterozygous black fur phenotype is

I think that b is the correct