Since a pound of sugar increases proportionally to the total cost of sugar bought, then the function can be written as:
c(p) = 0.42p
Where: c(p) = total cost of sugar bought
p = pounds of sugar
c(p) is a function of p, because c(p) depends on p.
Answer:
![E(X) = 4*0.2 +3*0.5+ 2*0.2 +1*0.8+ 0*0.02= 2.78](https://tex.z-dn.net/?f=%20E%28X%29%20%3D%204%2A0.2%20%2B3%2A0.5%2B%202%2A0.2%20%2B1%2A0.8%2B%200%2A0.02%3D%202.78)
So then the best answer for this case would be:
C. 2.78
Step-by-step explanation:
For this case we have the following probabability distribution function given:
Score P(X)
A= 4.0 0.2
B= 3.0 0.5
C= 2.0 0.2
D= 1.0 0.08
F= 0.0 0.02
______________
Total 1.00
The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.
If we use the definition of expected value given by:
![E(X) = \sum_{i=1}^n X_i P(X_I)](https://tex.z-dn.net/?f=%20E%28X%29%20%3D%20%5Csum_%7Bi%3D1%7D%5En%20X_i%20P%28X_I%29)
And if we replace the values that we have we got:
![E(X) = 4*0.2 +3*0.5+ 2*0.2 +1*0.8+ 0*0.02= 2.78](https://tex.z-dn.net/?f=%20E%28X%29%20%3D%204%2A0.2%20%2B3%2A0.5%2B%202%2A0.2%20%2B1%2A0.8%2B%200%2A0.02%3D%202.78)
So then the best answer for this case would be:
C. 2.78
Count how many pieces there are and then seer how many is that specific Piece and for percentage make it 100% of this amount then divide the different one out
65 people=20 minutes
20*3=60 minutes which is 1 hour
65*3=195 people per hour (This is the rate per hour)
195*6=1,170 people per six hours
Answer:
3/6 or 1/2 (50%)
Step-by-step explanation:
There is 6 containers of each flavor, correct?
If you pick 3 of the same flavor, 3/6, it would look like that fraction.
If you simplify it, It'd be 1/2.
If you want it as a percent, It'd be 50%.
As a decimal, It's .50.