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2 years ago

From what side of the vessel should you never anchor

Engineering

1 answer:

Pavel [41]2 years ago

6 0

Answer:

Never anchor from the stern as this can cause the boat to swamp.

Explanation:

Brainliest pls

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Thermodynamics fill in the blanks The swimming pool at the local YMCA holds roughly 749511.5 L (749511.5 kg) of water and is kep

Talja [164]

Answer:

$95.914\ \text{GJ}$

$\$272.78$

Explanation:

m = Mass of water = 749511.5 kg

c = Specific heat of water = 4182 J/kg ⋅°C

$\Delta T$ = Change in temperature = $80.6-50=30.6^{\circ}\text{F}$

Cost of 1 GJ of energy = $2.844

Heat required is given by

$Q=mc\Delta T\\\Rightarrow Q=749511.5\times 4182\times 30.6\\\Rightarrow Q=95.914\times 10^9\ \text{J}=95.914\ \text{GJ}$

Amount of heat required to heat the water is $95.914\ \text{GJ}$ .

Cost of heating the water is

$95.914\times 2.844=\$272.78$

Cost of heating the water to the required temperature is $\$272.78$ .

7 0

2 years ago

A 11-cm-diameter horizontal jet of water with a velocity of 40 m/s relative to the ground strikes a flat plate that is moving in

Reika [66]

Answer:

F = 8552.7N

Explanation:

We need first our values, that are,

$V_{jet} = 40m/s\\V_{Plate} = 10m/s \\D = 11cm$

We start to calculate the relative velocity, that is,

$V_r = V_{jet}-V_{plate}\\V_r = (40)-(10)\\V_r = 30m/s$

With the relative velocity we can calculate the mass flow rate, given by,

$\dot{m}_r = \rho A V_r$

$\dot{m}_r = (1000)(30) \frac{\pi (0.11)^2}{4}$

$\dot{m}_r = 285.09kg/s$

We need to define the Force in the direction of the flow,

$\sum\vec{F} = \sum_{out} \beta\dot{m}\vec{V} - \sum_{in} \beta\dot{m} \vec{V}\\$

$F = \dot{m}V_r$

$F = (285.09Kg/s)(30)$

$F = 8552.7N$

8 0

3 years ago

Serves as a protective barrier to prevent contact with engergized ("hot") parts<br> within the unit

erik [133]

Answer:

thanks hot hot

Explanation:

4 0

3 years ago

The weatherman states that the current temperature is 95 F and the dew point is 74 F. What is the current relative humidity?

spayn [35]

Answer:

Current Relative Humidity is 29.623

Given:

Current Temperature, $T_{c} = 95 F = 35^{\circ}C$

Dew point temperature, $T_{d} = 74 F = 23.34^{\circ}C$

Solution:

Now, in order to calculate the Relative Humidity, RH, we use the given formula:

$T_{d} =100( \frac{\frac{aT_{c}}{b + T}b + lnRH}{a - \frac{aT_{c}}{b + T} + lnRH})$

where

a = 17.625

b = 237.7

Now, using the above formula and given values:

$23.34 = (237.7\frac{\frac{17.625\times 35}{ 237.7 + 35} + lnRH}{17.625 - \frac{17.625\times 35}{237.7 + 35} + lnRH})$

$23.34(17.625 - 2.26 + lnRH) = (237.7\times 2.26 + lnRH)$

$358.62 + 23.34lnRH) = (537.20 + lnRH)$

On solving the above eqn, we get:

RH = 29.623

3 0

3 years ago

Two transmission belts pass over a double-sheaved pulley that is attached to an axle supported by bearings at A and D. The radiu

Fynjy0 [20]

Answer:

Check the explanation

Explanation:

Kindly check the attached image below to see the step by step explanation to the question above.

6 0

3 years ago