Answer: d) Inductors
Explanation: Inductors are the electric component commonly known by the name of coils as well. The work done by inductors is when the electric current flows through the coils of the wire then there is production of the magnetic field. They are the component that have the inductance in particular amount according to the circuit.So, coils of various dimensions are designed to introduce specified amount of inductance into a circuit are called inductors.
The coefficient of static friction is the ratio of the maximum static friction force (F) between the surfaces in contact before movement commences to the normal (N) force.
<h3>What is coefficient of static friction formula?</h3>
- The friction coefficient is the ratio of the normal force pushing two surfaces together to the frictional force preventing motion between them.
- Typically, it is represented by the Greek letter mu (). In terms of math, is equal to F/N, where F stands for frictional force and N for normal force.
- The ratio of the greatest static friction force (F) between the surfaces in contact before movement starts to the normal force (N) is known as the coefficient of static friction.
- A body and a surface have static and kinetic friction coefficients of 0.75 and 0.5, respectively. The body is forced to slide with a constant acceleration that is equal to A. g4 by applying a force.
Find the attachment answer.
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Answer:
i) 3750 veh/hr/ln
ii) 100 veh/mi/In
iii) 37.5 mph
Explanation:
number of lanes = 3
sf for both directions = 75 mph ( free mean speed )
Dj for both directions = 200 veh/mi/In
<u>Calculate the value of S0, D0 (veh/mi/ln) and maximum Vm (veh/hr)</u>
For either direction we will consider the total volume = 3 lanes
value of Dj = 3 lanes * 200 = 600 veh/mi/
i) value of SO
= ( Dj * sf ) / 4 = ( 600 * 75 ) / 4 = 11250 veh/hr = 3750 veh/hr/lane
ii) Value of DO
DO = Dj / 2 = 200 /2 = 100 veh/mi/In
iii) Value of Vm
= sf /2 = 75 / 2 = 37.5 mph
Answer:
Explanation:
Low frequency gain is= 40db= 20logK=>100 poles at 2MHz,20MHz
Zero at -200MHz, zero at infinity.
A) A(s) = 100FH(s)
B) Poles (1): 2 pi × 2 × 10^6= 4pi × 10^6MHz
(2): 2pi × 20 × 10^6= 4pi × 10^6 MHz
Zeroed: 2pi × 10^6 × 200= 400pi × 10^6, at infinity.
T/(S) = (1 + S/400π × 10^6)/S(1 + S/4π × 10^6)(1 + S/4π × 10^6)