During some actual expansion and compression processes in piston-cylinder devices, the gases have been are the P1= P2.
<h3>What is the pressure?</h3>
Pressure is something that has the pressure that is physical and that causes the pressure is piston-cylinder devices.
During a few real enlargements and compression procedures in piston-cylinder devices, the gases were located to meet the connection PV n = C, wherein n and C are constants.
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Answer:
The percentage ductility is 35.5%.
Explanation:
Ductility is the ability of being deform under applied load. Ductility can measure by percentage elongation and percentage reduction in area. Here, percentage reduction in area method is taken to measure the ductility.
Step1
Given:
Diameter of shaft is 10.2 mm.
Final area of the shaft is 52.7 mm².
Calculation:
Step2
Initial area is calculated as follows:


A = 81.713 mm².
Step3
Percentage ductility is calculated as follows:


D = 35.5%.
Thus, the percentage ductility is 35.5%.
Answer:
the MTTF of the transceiver is 50.17
Explanation:
Given the data in the question;
failure modes = 0.1 failure per hour
system reliability = 0.85
mission time = 5 hours
Now, we know that the reliability equation for this situation is;
R(t) = [ 1 - ( 1 -
)³] 
so we substitute
R(5) = [ 1 - ( 1 -
)³]
= 0.85
[ 1 - ( 1 -
)³]
= 0.85
[ 1 - ( 0.393469 )³]
= 0.85
[ 1 - 0.06091 ]
= 0.85
0.9391
= 0.85
= 0.85 / 0.9391
= 0.90512
MTTF = 5 / -ln( 0.90512 )
MTTF = 50.17
Therefore, the MTTF of the transceiver is 50.17
Answer:
A piece of code hidden in spread sheet
Answer:
The answer is V = √2FD ÷ CD × PA
Explanation:
FD = CD × PV²A ÷ 2
V² = 2FD ÷ CD × PA
V = √2FD ÷ CD × PA
Thus, The value of V is V = √2FD ÷ CD × PA
<u>-TheUnknownScientist 72</u>