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Rainbow [258]
2 years ago
5

10. What refrigerant is no longer manufactured in the United States?

Engineering
2 answers:
son4ous [18]2 years ago
6 0

Answer:

Freon Refrigerant Is Now Banned in the US

As of January 1, 2020, a once very popular air conditioning refrigerant can no longer be made in or imported into the United States.

Please give me brainliest -  you get 25% as well! I swear!

irina [24]2 years ago
5 0

Answer:

Freon Refrigerant

Explanation:

As of January 1, 2020 Freon Refrigerant can no longer be manufactured or imported to the United States. This is because R-22 (the principal component in Freon) has been banned in the states. Along with other greenhouse gasses, due to their contribution to damaging Earth’s ozone layer and global warming.

hope this helps:)

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In addition to bandages and gauze, it's recommended that a first aid kit also contain ___________. A) A finger splintB) Portable
valina [46]

Answer: (D: Tweezers)

A basic first aid kit is always good to have in case of an emergency. The typical items found in a first aid kit are pain reliever, tweezers, alcohol wipes, gloves, antiseptic, medical tape, sterile gauze, insect bite swaps, triple-antibiotic ointment, hydrogen peroxide, bandage scissors, instant cold compresses, and of course bandages. There are various types of bandages that can be included; elastic bandages, adhesive bandages, and triangular bandages for starters.

Explanation:

4 0
3 years ago
A cylindrical specimen of a titanium alloy having an elastic modulus of 107 GPa (15.5 × 106 psi) and an original diameter of 3.7
Keith_Richards [23]

Answer:

the maximum length of specimen before deformation is found to be 235.6 mm

Explanation:

First, we need to find the stress on the cylinder.

Stress = σ = P/A

where,

P = Load = 2000 N

A = Cross-sectional area = πd²/4 = π(0.0037 m)²/4

A = 1.0752 x 10^-5 m²

σ = 2000 N/1.0752 x 10^-5 m²

σ = 186 MPa

Now, we find the strain (∈):

Elastic Modulus = Stress / Strain

E = σ / ∈

∈ = σ / E

∈ = 186 x 10^6 Pa/107 x 10^9 Pa

∈ = 1.74 x 10^-3 mm/mm

Now, we find the original length.

∈ = Elongation/Original Length

Original Length = Elongation/∈

Original Length = 0.41 mm/1.74 x 10^-3

<u>Original Length = 235.6 mm</u>

5 0
3 years ago
If you are setting up a race car. What is the cross weight? Does it matter?
lara31 [8.8K]

Answer:

cross-weight is used to tighten it up.

Explanation:

and yes this is important because Cross-weight percentage compares the diagonal weight totals to the car's total weight.

hope  this help

(mark this answer as an brainliest answer)

7 0
4 years ago
2. BCD uses 6 bits to represent a symbol. a) True b) False​
Goshia [24]

Answer:

true because BCD used 6 bits to represent a symbol .

Explanation:

mark me brainlist

4 0
3 years ago
A large particle composite consisting of tungsten particles within a copper matrix is to be prepared. If the volume fractions of
OverLord2011 [107]

Answer:

Upper bounds 22.07 GPa

Lower bounds 17.59 GPa

Explanation:

Calculation to estimate the upper and lower bounds of the modulus of this composite.

First step is to calculate the maximum modulus for the combined material using this formula

Modulus of Elasticity for mixture

E= EcuVcu+EwVw

Let pug in the formula

E =( 110 x 0.40)+ (407 x 0.60)

E=44+244.2 GPa

E=288.2GPa

Second step is to calculate the combined specific gravity using this formula

p= pcuVcu+pwTw

Let plug in the formula

p = (19.3 x 0.40) + (8.9 x 0.60)

p=7.72+5.34

p=13.06

Now let calculate the UPPER BOUNDS and the LOWER BOUNDS of the Specific stiffness

UPPER BOUNDS

Using this formula

Upper bounds=E/p

Let plug in the formula

Upper bounds=288.2/13.06

Upper bounds=22.07 GPa

LOWER BOUNDS

Using this formula

Lower bounds=EcuVcu/pcu+EwVw/pw

Let plug in the formula

Lower bounds =( 110 x 0.40)/8.9+ (407 x 0.60)/19.3

Lower bounds=(44/8.9)+(244.2/19.3)

Lower bounds=4.94+12.65

Lower bounds=17.59 GPa

Therefore the Estimated upper and lower bounds of the modulus of this composite will be:

Upper bounds 22.07 GPa

Lower bounds 17.59 GPa

7 0
3 years ago
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