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Rainbow [258]
2 years ago
5

10. What refrigerant is no longer manufactured in the United States?

Engineering
2 answers:
son4ous [18]2 years ago
6 0

Answer:

Freon Refrigerant Is Now Banned in the US

As of January 1, 2020, a once very popular air conditioning refrigerant can no longer be made in or imported into the United States.

Please give me brainliest -  you get 25% as well! I swear!

irina [24]2 years ago
5 0

Answer:

Freon Refrigerant

Explanation:

As of January 1, 2020 Freon Refrigerant can no longer be manufactured or imported to the United States. This is because R-22 (the principal component in Freon) has been banned in the states. Along with other greenhouse gasses, due to their contribution to damaging Earth’s ozone layer and global warming.

hope this helps:)

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6. During some actual expansion and compression processes in piston–cylinder devices, the gases have been
Katyanochek1 [597]

During some actual expansion and compression processes in piston-cylinder devices, the gases have been are the P1= P2.

<h3>What is the pressure?</h3>

Pressure is something that has the pressure that is physical and that causes the pressure is piston-cylinder devices.

During a few real enlargements and compression procedures in piston-cylinder devices, the gases were located to meet the connection PV n = C, wherein n and C are constants.

Read more about the pressure :

brainly.com/question/25736513

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5 0
2 years ago
A 10.2 mm diameter steel circular rod is subjected to a tensile load that reduces its cross- sectional area to 52.7 mm^2. Determ
VMariaS [17]

Answer:

The percentage ductility is 35.5%.

Explanation:

Ductility is the ability of being deform under applied load. Ductility can measure by percentage elongation and percentage reduction in area. Here, percentage reduction in area method is taken to measure the ductility.

Step1

Given:

Diameter of shaft is 10.2 mm.

Final area of the shaft is 52.7 mm².

Calculation:

Step2

Initial area is calculated as follows:

A=\frac{\pi d^{2}}{4}

A=\frac{\pi\times(10.2)^{2}}{4}

A = 81.713 mm².

Step3

Percentage ductility is calculated as follows:

D=\frac{A_{i}-A_{f}}{A_{i}}\times100

D=\frac{81.713-52.7}{81.713}\times100

D = 35.5%.

Thus, the percentage ductility is 35.5%.

5 0
3 years ago
Three communications channels in parallel have independent failure modes of 0.1 failure per hour. These components must share a
ozzi

Answer:

the MTTF of the transceiver is 50.17

Explanation:

Given the data in the question;

failure modes = 0.1 failure per hour

system reliability = 0.85

mission time =  5 hours

Now, we know that the reliability equation for this situation is;

R(t) = [ 1 - ( 1 - e^{-0.1t )³] e^{-t/MTTF

so we substitute

R(5) = [ 1 - ( 1 - e^{-0.1(5) )³] e^{-5/MTTF = 0.85

[ 1 - ( 1 - e^{-0.5 )³] e^{-5/MTTF = 0.85

[ 1 - ( 0.393469 )³] e^{-5/MTTF = 0.85

[ 1 - 0.06091 ] e^{-5/MTTF = 0.85

0.9391 e^{-5/MTTF = 0.85  

e^{-5/MTTF = 0.85 / 0.9391

e^{-5/MTTF = 0.90512

MTTF = 5 / -ln( 0.90512 )

MTTF = 50.17

Therefore, the MTTF of the transceiver is 50.17

7 0
3 years ago
Which of the following describes a logic bomb?
dem82 [27]

Answer:

A piece of code hidden in spread sheet

8 0
3 years ago
FD=CD*((P*(V^2)*A)/2)<br><br>Please solve for V
REY [17]

Answer:

The answer is V = √2FD ÷ CD × PA

Explanation:

FD = CD × PV²A ÷ 2

V² = 2FD ÷ CD × PA

V = √2FD ÷ CD × PA

Thus, The value of V is V = √2FD ÷ CD × PA

 

<u>-TheUnknownScientist 72</u>

7 0
2 years ago
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