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Karolina [17]
3 years ago
13

The candle is lit and dilute ethanoic acid is poured down the inside of the beaker. As the acid reacts with the baking soda, bub

bles of CO2 gas form. After a few seconds
the air in the beaker is replaced by 0.20 liter of CO2 gas, causing candle flame to go out. The density of CO2 gas is 1.8 grams per liter at room temperature.
Choose the correct structural formula for the acid that was poured into the beaker.

Chemistry
1 answer:
nika2105 [10]3 years ago
5 0

Answer:

It’s answer #2

Explanation:

I only know this because i just got it wrong

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ASAP
sammy [17]

The answer is C.

The vast difference in electronegativity of the oxygen and hydrogen in water, the O-H bond is polar.

8 0
2 years ago
What is a substance consisting of two or more elements?
bixtya [17]
When two distinct elements are chemically combined—i.e., chemical bonds form between their atoms—the result is called a chemical compound<span>. Most elements on Earth bond with other elements to form chemical compounds, such as sodium (Na) and Chloride (Cl), which combine to form table salt (NaCl).

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5 0
3 years ago
Determina el pH del café cuya concentración de H+ es de 0.00001M
lara31 [8.8K]

Answer:

5

Explanation:

Given parameters:

Hydrogen ion concentration  =  0.00001M

Unknown:

pH of the solution =?

Solution:

The pH is used to estimate the degree of acidity or alkalinity of a solution. To solve for pH of any solution, we use the expression below;

          pH  = -log [H⁺]

[H⁺] is the hydrogen ion concentration

        pH  = -log (1 x 10⁻⁵)

      pH = -(-5) = 5

4 0
3 years ago
At an elevated temperature, Kp=4.2 x 10^-9 for the reaction 2HBr (g)---&gt; +H2(g) + Br2 (g). If the initial partial pressures o
Damm [24]

Answer : The partial pressure of H_2 at equilibrium is, 1.0 × 10⁻⁶

Explanation :

The partial pressure of HBr = 1.0\times 10^{-2}atm

The partial pressure of H_2 = 2.0\times 10^{-4}atm

The partial pressure of Br_2 = 2.0\times 10^{-4}atm

K_p=4.2\times 10^{-9}

The balanced equilibrium reaction is,

                                2HBr(g)\rightleftharpoons H_2(g)+Br_2(g)

Initial pressure    1.0×10⁻²       2.0×10⁻⁴      2.0×10⁻⁴

At eqm.            (1.0×10⁻²-2p)   (2.0×10⁻⁴+p)  (2.0×10⁻⁴+p)

The expression of equilibrium constant K_p for the reaction will be:

K_p=\frac{(p_{H_2})(p_{Br_2})}{(p_{HBr})^2}

Now put all the values in this expression, we get :

4.2\times 10^{-9}=\frac{(2.0\times 10^{-4}+p)(2.0\times 10^{-4}+p)}{(1.0\times 10^{-2}-2p)^2}

p=-1.99\times 10^{-4}

The partial pressure of H_2 at equilibrium = (2.0×10⁻⁴+(-1.99×10⁻⁴) )= 1.0 × 10⁻⁶

Therefore, the partial pressure of H_2 at equilibrium is, 1.0 × 10⁻⁶

4 0
3 years ago
Which subatomic particle is located outside the nucleus
Mrac [35]
Electrons is located outside the nucleus
5 0
3 years ago
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