1: parent alkane.
2: polymers
3: idk
4: alkynes
5: its either n-butane or isobutane
6: saturated hydrocarbons
7: i'm not sure but I think it's Lewis Dot Structure and Polarity. ... Benzene
8: Idk
9: I'm not sure either
Hope this helps! :)
Answer:
[KI] = 0.17 M
Explanation:
We determine the moles of solute:
Mass / Molar mass → 4.73 g / 166 g/mol = 0.0285 moles
Molarity (mol/L) is defined as moles of solute in 1L of solution
It is a sort of concentration
M = 0.0285 mol / 0.169L = 0.17 M
Instead of making the division (mol/L), we can also try this rule of three:
In 0.169 L we have 0.0285 moles of solute
in 1 L we must have ___ (1 . 0.0285) / 0.169 = 0.17 mol/L
Answer:
It depends what the compound is.
Explanation:
You need to use Avogadro's number (6.22*10^23) to convert the number of molecules of a compound to moles of the compound. From there, you can use the molar mass of the compound (grams per mole) to get the mass. You can get the molar mass by googling "molar mass of [compound]" or calculate it yourself using the periodic table.
So: 8.2*10^11 molecules of the compound * (1 mole of the compound/6.022*10^23 molecules of the compound) * (# of grams/1 mole of the compound)
Answer:
3–ethyl–4–methylhexane.
Explanation:
To name the above compound, do the following:
1. Determine the functional group of the compound.
2. Locate the longest continuous carbon chain. This gives the parent name of the compound.
3. Identify the substituent group attached to the compound.
4. Give the substituent the lowest possible count.
5. Combine the above to name the compound.
Now, we shall name the compound given in the question above as follow:
1. The compound contains only single bond. Therefore, the compound belong to the alkane family.
2. The longest continuous carbon chain is 6 i.e hexane.
3. The substituent group attached are:
i. Methyl, CH3.
ii. Ethyl, CH2CH3.
4. we shall name the substituents alphabetically i.e ethly will come before methyl. Therefore,
Ethyl is located at carbon 3.
Methy is located at carbon 4.
5. Therefore, the name of the compound is:
3–ethyl–4–methylhexane.
