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BARSIC [14]
2 years ago
14

PLS HELP CHEM

Chemistry
1 answer:
Bess [88]2 years ago
7 0

Answer:

Use the formula PV=nRT to get the temperature

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amm1812

Answer:

dnaq tester

Explanation:

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3 years ago
Scientists tracking the populations of certain freshwater fish have found an increase in the female to male ratio of several sma
vodomira [7]
I believe that the answer to the question provided above is that <span>they formed two very different hypotheses since it is what they saw according to what they knew. Also hypothesis is just an intelligent guess.</span>
Hope my answer would be a great help for you.    If you have more questions feel free to ask here at Brainly.
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3 years ago
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A chemistry graduate student is given of a chlorous acid solution. Chlorous acid is a weak acid with . What mass of should the s
DerKrebs [107]

Answer:

11.31g NaClO₂

Explanation:

<em> Is given 250mL of a 1.60M chlorous acid HClO2 solution. Ka is 1.110x10⁻². What mass of NaClO₂ should the student dissolve in the HClO2 solution to turn it into a buffer with pH =1.45? </em>

It is possible to answer this question using Henderson-Hasselbalch equation:

pH = pKa + log₁₀ [A⁻] / [HA]

<em>Where pKa is -log Ka = 1.9547; [A⁻] is the concentration of the conjugate base (NaClO₂), [HA] the concentration of the weak acid</em>

You can change the concentration of the substance if you write the moles of the substances:

[Moles HClO₂] = 250mL = 0.25L×(1.60mol /L) = <em>0.40 moles HClO₂</em>

Replacing in H-H expression, as the pH you want is 1.45:

1.45 = 1.9547 + log₁₀ [Moles NaClO₂] / [0.40 moles HClO₂]

-0.5047 = log₁₀ [Moles NaClO₂] / [0.40 moles HClO₂]

<em>0.3128 = </em>[Moles NaClO₂] / [0.40 moles HClO₂]

0.1251 = Moles NaClO₂

As molar mass of NaClO₂ is 90.44g/mol, mass of 0.1251 moles of NaClO₂ is:

0.1251 moles NaClO₂ ₓ (90.44g / mol) =

<h3>11.31g NaClO₂</h3>
5 0
3 years ago
If a gas is cooled from 343.0 K to 283.15 K and the volume is kept constant what final pressure would result if the original pre
mario62 [17]

Answer:

627.4 mmHg

Explanation:

From Gay-Lussac law:

\frac{p1}{t1}  =  \frac{p2}{t2}

p1 = 760 mmHg

t1 = 343 K

t2=283.15 K

p2 = p1 \times  \frac{t2}{t1}

p2 = 760 \times  \frac{283.15}{343.0}

p2 = 627.4 \: mmhg

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use the formula force=mass × acceleration to find the force of a 20 kg cart rolling at an acceleration of .5 m/s​
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Answer:

The answer is 10

Explanation:

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