Formula= P4O6
You are going to want to flip the elements subscripts with one another.
P6O4
P will just stay as phosphorus, but since oxygen has 4 atoms, itbwill become tetroxide
Two months later 13.8 milligrams of the barium-131 still be radioactive.
<h3>How is the decay rate of a radioactive substance expressed ? </h3>
It is expressed as:

where,
A = Amount remaining
A₀ = Initial Amount
t = time
T = Half life
Here
A₀ = 0.50g
t = 2 months = 60 days
T = 11.6 days
Now put the values in above expression we get



= 0.50 × 0.0277
= 0.0138 g
= 13.8 mg [1 mg = 1000 g]
Thus from the above conclusion we can say that Two months later 13.8 milligrams of the barium-131 still be radioactive.
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Question: Suppose that 0.50 grams of ban that 0.50 grams of barium-131 are administered orally to a patient. Approximately many milligrams of the barium would still be radioactive two months later? The half-life of barium-131 is 11.6 days.
Answer: The percent yield for the
is, 86.7 %
Explanation : Given,
Moles of
= 2.36 mol
Moles of
= 6.14 mol
First we have to calculate the moles of
The balanced chemical equation is:
From the reaction, we conclude that
As, 2 moles of
react to give 6 moles of
So, 2.36 moles of
react to give
mole of
Now we have to calculate the percent yield for the
.
Experimental yield = 6.14 moles
Theoretical yield = 7.08 moles
Now put all the given values in this formula, we get:
Therefore, the percent yield for the
is, 86.7 %
In this solution we are having two components i.e. NaCl and H₂O. So the %age mass of NaCl is calculated by following formula,
%age mass of NaCl = (Mass of NaCl / Mass of NaCl + Mass of H₂O) × 100 ------ (1)
Calculating Mass of NaCl at 50°C;
Solubility of NaCl was searched online and was found 36.69 g / 100 mL of water at 50 °C.
Calculating Mass of 100 mL H₂O at 50°C;
Density of H₂O at 50 °C is 0.988 g/ml, so for 100 mL
As,
Density = Mass / Volume
Mass = Density × Volume
Mass = 0.988 g/mL × 100 mL
Mass = 98.8 g
Putting Masses of NaCl and H₂O in eq. 1,
%age mass of NaCl = (36.69 g / 36.69 g + 98.8 g) × 100
%age mass of NaCl = (36.69 g / 135.49 g) × 100
%age mass of NaCl = 27.07 %