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Tatiana [17]
2 years ago
8

"Express the difference in the measures of center as a multiple of each measure of variation. Round your answers to the nearest

tenth.
The difference in the medians is about (ANSWER HERE) to (ANSWER HERE) times the IQR."

The picture attached is the info needed to solve it. Someone please help, I'm completely lost.​

Mathematics
1 answer:
zimovet [89]2 years ago
8 0

Answer:

unsure but i think the first one

Step-by-step explanation:

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A new car depreciates as soon as you drive it out of the parking lot. A certain car depreciates to half its original value in 4
Alexandra [31]

Answer:

Original price of car = $20,000

Step-by-step explanation:

Let the original price of the car be 'x' dollars.

Given:

Here, the depreciation of the car is occuring exponentially as the value depreciates to half in every four years.

Worth of car after 8 years = $5000

Value after depreciation in 4 years = Half of original value = \frac{x}{2}

So, value of car after depreciation in another 4 years = Half of the value after 4 years = \frac{1}{2}(\frac{x}{2})=\frac{x}{4}

Therefore, final depreciated value after 8 years is \frac{x}{4}.

But, as per question, final depreciated value is $5000. Thus,

\frac{x}{4}=5000\\x=5000\times 4\\x=20000

Therefore, the original price of the car was $20,000.

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2 years ago
If you have 2 linear equations and you want to find where they have the same x- and y- value on a graph you look for the
marin [14]

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If 1200 cm2 of material is available to make a box with a square base and an open top, find the largest possible volume of the b
Colt1911 [192]

Answer:

The largest possible volume V is ;

V = l^2 × h

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Step-by-step explanation:

Given

Volume of a box = length × breadth × height= l×b×h

In this case the box have a square base. i.e l=b

Volume V = l^2 × h

The surface area of a square box

S = 2(lb+lh+bh)

S = 2(l^2 + lh + lh) since l=b

S = 2(l^2 + 2lh)

Given that the box is open top.

S = l^2 + 4lh

And Surface Area of the box is 1200cm^2

1200 = l^2 + 4lh ....1

Making h the subject of formula

h = (1200 - l^2)/4l .....2

Volume is given as

V = l^2 × h

V = l^2 ×(1200 - l^2)/4l

V = (1200l - l^3)/4

the maximum point is at dV/dl = 0

dV/dl = (1200 - 3l^2)/4

dV/dl = (1200 - 3l^2)/4 = 0

3l^2= 1200

l^2 = 1200/3 = 400

l = √400

I = 20cm

Since,

h = (1200 - l^2)/4l

h = (1200 - 20^2)/4×20

h = (800)/80

h = 10cm

The largest possible volume V is ;

V = l^2 × h

V = 20^2 × 10 = 4000cm^3

4 0
3 years ago
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