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dmitriy555 [2]
3 years ago
11

Identify the only polyatomic ion below that is NOT an oxyanion. Your answer: A Cyanide B Nitrate C Hydroxide D Sulfate​

Chemistry
1 answer:
DochEvi [55]3 years ago
7 0

Answer:

Cyanide

Explanation:

<em>Molecular Structure of Each Answer</em>

A:  CN-

B: NO3-

C: OH-

D: SO4 2-

As you can see, only A (Cyanide) is the only compound that does not contain oxygen, meaning it is NOT an oxyanion.

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Un átomo neutro tiene número atómico 1 y número másico 3. Indica cuántos protones, neutrones y electrones tiene.
ahrayia [7]

Answer:

El átomo podes 1 protón, 1 electrón y 2 neutrones.

Explanation:

Cada elemento químico se caracteriza por el número de protones de su núcleo, que se denomina número atómico Z. Es decir, el número atómico​ de un elemento químico es el número total de protones que tiene cada átomo de ese elemento.

Los protones poseen carga positiva y se encuentran en el núcleo, en torno al cual se mueven otras partículas con carga eléctrica negativa que son los electrones. Así, el átomo es eléctricamente neutro, ya que la carga positiva de los protones está compensada por la carga negativa de los electrones.  Entonces, en todo átomo neutro el número de protones del núcleo es igual al de electrones de sus orbitales.

En este caso, un átomo neutro tiene número atómico 1. Entonces la cantidad de protones y electrones presentes en el átomo es 1.

En el núcleo de cada elemento, además de protones, también es posible encontrar neutrones, cuyo número puede variar. La masa atómica (A) se obtiene sumando el número de protones y de neutrones de un núcleo determinado:

Número másico (A) = número de protones + número de neutrones

En este caso, el átomo neutro posee 1 protón y su número másico es 3. Entonces:

3= 1 + número de neutrones

Resolviendo:

3 - 1= número de neutrones

2= número de neutrones

Entonces,<u><em> el átomo podes 1 protón, 1 electrón y 2 neutrones.</em></u>

6 0
3 years ago
Calculate the standard reaction enthalpy for the reaction NO2(g) → NO(g) + O(g) given +142.7 kJ/mol for the standard enthalpy of
bulgar [2K]

Answer:

The standard reaction enthalpy for the given reaction is 235.15 kJ/mol.

Explanation:

O_2(g) \rightarrow \frac{2}{3}O_3(g),\Delta H^o_{1}=142.7 kJ/mol..[1]

O_2(g) \rightarrow 2 O(g),\Delta H^o_{2}=498.4 kJ/mol..[2]

NO(g) + O_3(g)\rightarrow NO_2(g) + O_2(g) ,\Delta H^o_{3} = -200 kJ/mol..[3]

NO_2(g)\rightarrow NO(g) + O(g),\Delta H^o_{4}=?..[4]

Using Hess's law:

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

2 × [4] = [2]- (3 ) × [1] - (2) × [3]

2\times \Delta H^o_{4}=\Delta H^o_{2} -3\times \Delta H^o_{1}-2\times \Delta H^o_{3}

2\times \Delta H^o_{4}=498.4 kJ/mol-3\times 142.7 kJ/mol-2\times -200 kJ/mol

2\times \Delta H^o_{4}=470.3 kJ/mol

\Delta H^o_{4}=\frac{470.3 kJ/mol}{2}=235.15 kJ/mol

The standard reaction enthalpy for the given reaction is 235.15 kJ/mol.

7 0
3 years ago
Rusting of iron is a very common chemical reaction. It results in one form from Fe reacting with oxygen gas to produce iron (III
Vlada [557]

<u>Answer:</u> The given amount of iron reacts with 9.0 moles of O_2 and produce 6.0 moles of Fe_2O_3

<u>Explanation:</u>

We are given:

Moles of iron = 12.0 moles

The chemical equation for the rusting of iron follows:

4Fe+3O_2\rightarrow 2Fe_2O_3

  • <u>For oxygen gas:</u>

By Stoichiometry of the reaction:

4 moles of iron reacts with 3 moles of oxygen gas

So, 12.0 moles of iron will react with = \frac{3}{4}\times 12.0=9.0mol of oxygen gas

  • <u>For iron (III) oxide:</u>

By Stoichiometry of the reaction:

4 moles of iron produces 2 moles of iron (III) oxide

So, 12.0 moles of iron will produce = \frac{2}{4}\times 12.0=6.0mol of iron (III) oxide

Hence, the given amount of iron reacts with 9.0 moles of O_2 and produce 6.0 moles of Fe_2O_3

5 0
3 years ago
What is pollination?
blagie [28]
Pollination is the act of transferring pollen grains from the male anther of a flower to the female stigma.

Hopefully that helped! Maybe just change up the words a bit <3
5 0
3 years ago
Examining the figure, how many orders of magnitude larger is a person than a bacterial cell?
Allushta [10]
Well you did not show the figure, but I can show you how to do it.

Suppose the person is 6 feet tall and the bacteria cell is 1 micrometer in length.

So, put both magnitudes in the same units. I will use meter.

Person: 6 feet * 0.3048 m / foot = 1.8288 m, which in orders of magnitud is about 2 m

Bacteria cell: 1 micrometer * 1 m / 1,000,000 micrometer = 1 * 10 ^ -6 m.

Now divide: 2m / 10^ -6 m = 2,000,000

So a person is about 2 million times larger than a bacteria cell.

If the numbers in your figure are different you can use the same method to get a new result according to your figure.
8 0
3 years ago
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