A savings account for a car is set up with an initial balance of $3000, and 125 is added every

Mathematics

1 answer:

zhuklara [117]3 years ago

6 0

Answer:

1) 3000 + 125m

2) 3000 + 125m = 5000

3) M= 16

4) It would take 16 months

Step-by-step explanation:

Okay so no since there are no other transaction and you already have a balance of 3000 with a monthly Fee of 125 the equation shpuld be like this.

So every month you add 125,we dont know how much months we have to pay so we can use the variable given to us in this case “M”. So your base expression should look like this,

3000 + 125m (3000 base fee that doesnt change, and 125 every month fee)

Then it asked us to put it as the final balance as 5000, so using the base expression we can do this

3000 + 125m = 5000

Now to solve it you would solve it like any other equation

5000-3000=2000

2000=125m

2000/125= 16

Okay so m = 16

M in this case stands for months so the final answer would be it would take 16 months to reach the final balance of 5000

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77julia77 [94]

Answer:

The interquartile range is 5.

Step-by-step explanation:

Ah, a throwback to interquartile range... let me help :)

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3 years ago

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write a linear equation that intersects y=x^2 at two points. Then write a second linear equation that intersects y=x^2 at just o

Liula [17]

We know that $y = x^2$ is a parabola, concave up, with vertex in the origin $(0,0)$

So, we may use three horizontal lines for our purpose: any horizontal line above the x axis will intersect the parabola twice. The x axis itself intersects the parabola once on the vertex, while any horizontal line below the x axis won't intercept the parabola.

Here's the examples:

The horizontal line $y = 4$ intercepts the parabola twice: the system $y = x^2,\ y = 4$ is solved by $x^2=4 \implies x = \pm 2$
The horizontal line $y=0$ intercepts the parabola only once: the system is $y=x^2,\ y=0$ which yields $x^2=0\implies x=0$ which is a repeated solution
The horizontal line $y=-5$ intercepts the parabola only once: the system is $y=x^2,\ y=-5$ which yields $x^2=-5$ which is impossible, because a squared number can't be negative.