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vivado [14]
3 years ago
13

Question 7 of 10

Physics
1 answer:
Vadim26 [7]3 years ago
5 0

Answer:

0.33s

Explanation:

hope this is the correct ans

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Calculate the inhomogeneity of a 1.5 t magnet
Ludmilka [50]
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6 0
3 years ago
John pushes his bed to the left overcoming the force of friction. On the free-body diagram below, which force represents the fri
mamaluj [8]

Answer:

<em>Force B</em>

Explanation:

<u>Friction Force </u>

It's a force that appears when an object is tried to move on a rough surface. There are two cases: when the object is at rest, we have the friction static coefficient and when the object is already moving, we have the dynamic coefficient. The static coefficient is usually greater than the second because it's harder to overcome the friction when the object is at rest.

We are told that John pushes the bed to the left with enough force to overcome the force of friction. If the movement is intended to be to the left side, the friction force appears to the right, since it always opposes to the movement. Thus the force B is the one who represents the friction force in this situation

6 0
4 years ago
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c. A car was running with a velocity of 20m/s. what will be its velocity after 30s if it's acceleration is 5m/s2​
weqwewe [10]

\large \mathfrak{Solution : }

let's use first equation of motion to solve this ;

  • \boxed{ \boxed{ v = u + at}}

  • v = 20 + (5 \times 30)

  • v = 20 + 150

  • v = 170 \:  \: m/s

Velocity after 30 seconds = 170 m/s

4 0
3 years ago
ate around its central axis. A rope wrapped around the drum of radius 1.24 m exerts a force of 4.56 N to the right on the cylind
Mashcka [7]

Answer:

Magnitude the net torque about its axis of rotation is 1.3338 Nm

Explanation:

The radius of the wrapped rope around the drum, r = 1.24 m

Force applied to the right side of the drum, F = 4.56 N

The radius of the rope wrapped around the core, r' = 0.57 m

Force on the cylinder in the downward direction, F' = 7.58 N

Now, the magnitude of the net torque is given by:

\tau_{net} = \tau + \tau'

where

\tau = Torque due to Force, F

\tau' = Torque due to Force, F'

\tau = F\times r\tau' = F'\times r'

Now,

\tau_{net} = - F\times r + F'\times r'\tau_{net} = - 4.56\times 1.24 + 7.58\times 0.57 \\\\= - 1.3338\ Nm

The net torque comes out to be negative, this shows that rotation of cylinder is in the clockwise direction from its stationary position.

Now, the magnitude of the net torque:

|\tau_{net}| = 1.3338\ Nm

8 0
3 years ago
Gasoline and propane fumes are most likely to accumulate in what part of the boat
aleksley [76]
The boat has a lot of parts that has a necessary part in order for it to move and for it to stop. But as the question above asks, the part where the gasoline and the propane fumes accumulate is in the bilge, which is one of the parts of the boat that is considered to be important.
7 0
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