Answer:
the position of the wood below the interface of the two liquids is 2.39 cm.
Explanation:
Given;
density of oil,
= 926 kg/m³
density of the wood,
= 974 kg/m³
density of water,
= 1000 kg/m³
height of the wood, h = 3.69 cm
Based on the density of the wood, it will position across the two liquids.
let the position of the wood below the interface of the two liquids = x
Let the wood be in equilibrium position;
![F_{wood} - F_{oil} - F_{water} = 0\\\\\rho _{wood} .gh - \rho _o .g(h-x) - \rho_w .gx = 0\\\\\rho _{wood} .h - \rho _o (h-x) - \rho_w .x = 0\\\\\rho _{wood} .h -\rho _o h + \rho _o x - \rho_w .x =0\\\\h (\rho _{wood} -\rho _o ) = x( \rho_w - \rho _o)\\\\x =h[\frac{ \rho _{wood} -\rho _o }{\rho_w - \rho _o} ]\\\\x = 3.69\ cm \times [\frac{974 - 926}{1000-926} ]\\\\x = 2.39 \ cm](https://tex.z-dn.net/?f=F_%7Bwood%7D%20-%20F_%7Boil%7D%20-%20F_%7Bwater%7D%20%3D%200%5C%5C%5C%5C%5Crho%20_%7Bwood%7D%20.gh%20-%20%5Crho%20_o%20.g%28h-x%29%20-%20%5Crho_w%20.gx%20%3D%200%5C%5C%5C%5C%5Crho%20_%7Bwood%7D%20.h%20-%20%5Crho%20_o%20%28h-x%29%20-%20%5Crho_w%20.x%20%3D%200%5C%5C%5C%5C%5Crho%20_%7Bwood%7D%20.h%20-%5Crho%20_o%20h%20%2B%20%5Crho%20_o%20x%20-%20%5Crho_w%20.x%20%3D0%5C%5C%5C%5Ch%20%28%5Crho%20_%7Bwood%7D%20%20-%5Crho%20_o%20%29%20%3D%20x%28%20%5Crho_w%20-%20%5Crho%20_o%29%5C%5C%5C%5Cx%20%3Dh%5B%5Cfrac%7B%20%5Crho%20_%7Bwood%7D%20%20-%5Crho%20_o%20%7D%7B%5Crho_w%20-%20%5Crho%20_o%7D%20%5D%5C%5C%5C%5Cx%20%3D%203.69%5C%20cm%20%5Ctimes%20%5B%5Cfrac%7B974%20-%20926%7D%7B1000-926%7D%20%5D%5C%5C%5C%5Cx%20%3D%202.39%20%5C%20cm)
Therefore, the position of the wood below the interface of the two liquids is 2.39 cm.
Answer:
Except in the crust, the interior of the Earth cannot be studied by drilling holes to take samples. Instead, scientists map the interior by watching how seismic waves from earthquakes are bent, reflected, sped up, or delayed by the various layers.
Explanation:
Answer:
gamma rays < X-ray < ultraviolet ray < visible light < infrared < radio wave
Explanation:
given light form,
A) radio waves,B) infrared,C) visible light,D) ultraviolet,E) X-rays,F) gamma rays
we know,
wavelength of radio wave = 10000 Km
wavelength of infrared = 700 nanometers (nm) to 1 millimeter (mm)
wavelength of visible light = 380 to 740 nm
wavelength of ultraviolet ray = 10 nm to 400 nm
wavelength of X-ray = 0.01 to 10 nm
wavelength of gamma rays = 100 picometer
so, the order of rays.
gamma rays < X-ray < ultraviolet ray < visible light < infrared < radio wave
Answer:
time is 5.973826 sec
Explanation:
Given data
diameter D = 6.0 mm 6×
m
separated d = 0.010 m
distance (dis) 185 m
speed s = 16 m/s
wavelength = 550 nm = 550
m
to find out
How much time passes
solution
we know that for resolution we use Rayleigh's Criterion i.e
θ = 1.22 wavelength / diameter = separated / distance 1
we calculate distance 1 by put value wavelength, diameter and separated
distance 1 = diameter × separated / 1.22 wavelength
distance 1 = 6×
× 0.010 / 1.22 × 550 × 
distance 1 = 89.418778
so time will be i.e = distance (dis) - distance 1 / speed
time = ( 185 - 89.418778) / 16
time = 5.973826 sec
time is 5.973826 sec