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Amanda [17]
3 years ago
6

Choose all the right answers.

Chemistry
1 answer:
pentagon [3]3 years ago
5 0

Answer:

I think by planting a spore

Explanation:

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What determines the strength of a dipole dipole force?
Reil [10]

Answer:

The more polar the molecules, the stronger the force. The more hydrogen in the molecule, the stronger the force.

Explanation:

I hope this helps and please ask if you need further help!

5 0
3 years ago
In which way are a prokaryotic cell and a eukaryotic cell alike?  
inessss [21]
Prokaryotic cells do not contain membrane-closed organelles, (??) and they are not the same size at all. (prokaryotic are way smaller) Just to help narrow down, if I'm right! (: Sorry, I know that's not completely helpful.
6 0
3 years ago
Read 2 more answers
Valence level
Degger [83]
B, C, D are compounds, while A and E are just element stand-alones.
3 0
3 years ago
Un átomo X posee 29 protones y de carga +2 ¿Cuántos electrones tiene?
lesya [120]

Responder:

27

Explicación:

Dado que:

Número de protones en el átomo X = 29

Carga en el átomo X = +2

Si no hay cargo neto;

número de protones = número de electrones

Sin embargo, dado que el átomo X tiene una carga de +2 (dando 2 electrones).

Por lo tanto,

Número de electrones = número de protones - número de carga en el átomo)

Número de electrones = (29 - 2) = 27

4 0
3 years ago
The volume of CO2 at 99.3 kPa was measured at 455 cm3. What will the volume be if the pressure is adjusted to 202.6 kPa?
Marizza181 [45]

Answer:

<h3>The answer is 223.0 cm³</h3>

Explanation:

To find the volume when the pressure is at 202.6 kPa we use Boyle's law which is

P_1V_1 = P_2V_2

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we are finding the final volume

V_2 =  \frac{P_1V_1}{P_2}  \\

From the question

P1 = 99.3 kPa = 99300 Pa

V1 = 455 cm³

P2 = 202.6 kPa = 202600

So we have

V_2 =  \frac{99300 \times 455}{202600}  =   \frac{45181500}{202600}  \\  = 223.008390...

We have the final answer as

<h3>223.0 cm³</h3>

Hope this helps you

6 0
4 years ago
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