I think the answer to this question is three or 3
Answer:
It can you just have to find a song that get's stuck in your head and try replacing the studing answer with the song because then the answer will get stuck in your head.
Explanation:
When encountering another vessel in darkness, the visible white, red and green lights indicate you are approaching a powerboat head-on.
In this case neither vessels has the right of way. Both boat operators must take early action to stay out of the way for other vessels. The operators must reduce their speed and steer to starboard.
<h2>Further Explanation</h2>
The visible white, red and green lights are all navigation lights with different purposes. However, the four common navigational lights are sidelights, sternlight, Masthead light and all-round white light.
Sidelights are also referred to as combination lights. It is the combination of red and green light and visible to another vessel that approaching head on or from the side. The green light is the boat starboard (right hand side) and the red light is the port side (left) of a vessel.
The sternlight is the white light seen from behind the vessel.
The masthead light is a white light. The white light shines forward to all sides of the vessels. It is on all power driven vessels.
All-round white light is a white light used to combine sternlight and masthead light to form a single white light so that it can boldly be seen by other vessels.
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KEYWORDS:
- boat
- head-on
- masthead light
- white light
- operators
1 is c 2 is b 3 is 1 d 4 is a
T<span>his is a straightforward question related to the surface energy of the droplet. </span>
<span>You know the surface area of a sphere is 4π r² and its volume is (4/3) π r³. </span>
<span>With a diameter of 1.4 mm you have an original droplet with a radius of 0.7 mm so the surface area is roughly 6.16 mm² (0.00000616 m²) and the volume is roughly 1.438 mm³. </span>
<span>The total surface energy of the original droplet is 0.00000616 * 72 ~ 0.00044 mJ </span>
<span>The five smaller droplets need to have the same volume as the original. Therefore </span>
<span>5 V = 1.438 mm³ so the volume of one of the smaller spheres is 1.438/5 = 0.287 mm³. </span>
<span>Since this smaller volume still has the volume (4/3) π r³ then r = cube_root(0.287/(4/3) π) = cube_root(4.39) = 0.4 mm. </span>
<span>Each of the smaller droplets has a surface area of 4π r² = 2 mm² or 0.0000002 m². </span>
<span>The surface energy of the 5 smaller droplets is then 5 * 0.000002 * 72.0 = 0.00072 mJ </span>
<span>From this radius the surface energy of all smaller droplets is 0.00072 and the difference in energy is 0.00072- 0.00044 mJ = 0.00028 mJ. </span>
<span>Therefore you need roughly 0.00028 mJ or 0.28 µJ of energy to change a spherical droplet of water of diameter 1.4 mm into 5 identical smaller droplets. </span>
