All categories

2 years ago

What is gama rays an it's uses

Physics

1 answer:

pav-90 [236]2 years ago

5 0

Answer:

GAMMA RAYS:

A photon emitted spontaneously by a radioactive substance also : a photon of higher energy than that of an X-ray.

USES OF GAMMA RAYS:

Gamma rays are used in medicine (radiotherapy), industry (sterilization and disinfection), and the nuclear industry. Shielding against gamma rays is essential because they can cause diseases to skin or blood, eye disorders, and cancers.

You might be interested in

Answer all these questions

Kazeer [188]

Answer:

mechanical waves,

the quality of a sound governed by the rate of vibrations producing it; the degree of highness or lowness of a tone.

If the amplitude increases the volume increases and vice versa.

The type of medium affects a sound wave as sound travels with the help of the vibration in particles.

The higher the frequency, the shorter the wavelength.

Explanation:

5 0

2 years ago

Read 2 more answers

Tarzan swings on a 31.0 m long vine initially inclined at an angle of 36.0◦ with the vertical. The acceleration of gravity if 9.

Gennadij [26K]

Answer:

$v=10.777m/s$

Explanation:

Tarzan swing can be thought of as change in potential energy by going from higher location We solve for height of beginning of the swing by using simple cosine equation:

$31Cos36=25.08\\E_{potential}=mgh\\$

ΔE=mg(h₂-h₁)

$=m*9.81(31-25.08)\\$

The potential energy of Tarzan initial position is converted into kinetic energy of his swing.By using kinetic equation

$E_{kinectic}=P_{potential}\\1/2mv^{2}=m*9.81(31.0-25.08)\\(1/2)v^{2}=9.81(31.0-25.08)\\0.5v^{2}=58.07\\v^{2}=58.07/0.5\\v=\sqrt{58.07/0.5}\\ v=10.777m/s$

8 0

3 years ago

An 820 N Marine in basic training climbs a 12.0-m vertical rope at a constant speed in 8.00 s. What is her power output

sweet-ann [11.9K]

Answer:

1230 W

Explanation:

P = $\frac{W}{t}$ = $\frac{Force * distance}{time}$ = $\frac{820 N * 12.0 m}{8.00 s}$ = 1230 Watts

6 0

3 years ago

A less massive moving object has an elastic collision with a more massive object that is not moving. Compare the initial velocit

stepladder [879]

Assume that the small-massed particle is $m$ and the heavier mass particle is $M$ .

Now, by momentum conservation and energy conservation:

$mv = mv_{m} + Mv_{M}$

$mv^{2} = mv^{2}_{m} + Mv^{2}_{M}$

Now, there are 2 solutions but, one of them is useless to this question's main point so I excluded that point. Ask me in the comments if you want the excluded solution too.

$v_{m} = v\frac{m - M}{m + M}\\\\\\v_{M} = v\frac{m + M}{m + M}\\$