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tiny-mole [99]
3 years ago
9

How do scientist use information about an object or event

Physics
1 answer:
Arlecino [84]3 years ago
4 0
Many ways for example they look up related things and study them or they can test it and see what happens
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A bus starting from rest moves with a uniform acceleration of 0.1 m s -2 for 2 minutes. Find (a) the speed acquired, (b) the dis
KiRa [710]

Answer:

S=720m anf vf=12m/s

Explanation:

acceleration=a=0.1m/s²

time taken=t=2minutes=2×60=120seconds

vi=0m/s

vf=?

distance covered=S=?

by using second equation of motion

S=vit+1/2at²

S=0m/s×120seconds+1/2(0.1m/s²)(120s)²

S=0m/s+1/2×1440m

S=720m

and now we have to find the vf

vf=vi+at

vf=0m/s+(0.1m/s)(120s)

vf=12m/s

i hope it will help you

8 0
3 years ago
Find the current in the 12 ohm resistor.
disa [49]

Answer:

1.5 A

Explanation:

V =I.R

18 = I × 12

I = 18/12

= 3/2 = 1.5 A

3 0
3 years ago
Witch of the following is the correct definition of convention
iogann1982 [59]

Answer:

A is the answer .(A) is correct

3 0
2 years ago
Diferencie energia cinética de energia potencial gravitacional.
Vikentia [17]

Answer:

Featured snippet from the web

The atoms and molecules in it are in constant motion. The kinetic energy of such a body is the measure of its temperature. Potential energy is classified depending on the applicable restoring force. Gravitational potential energy – potential energy of an object which is associated with gravitational force

4 0
3 years ago
What is the volume V of a sample of 4.00 mol of copper? The atomic mass of copper (Cu) is 63.5 g/mol, and the density of copper
rusak2 [61]

Answer : The volume of a sample of 4.00 mol of copper is 28.5cm^3

Explanation :

First we have to calculate the mass of copper.

\text{ Mass of copper}=\text{ Moles of copper}\times \text{ Molar mass of copper}

\text{ Mass of copper}=(4.00moles)\times (63.5g/mole)=254g

Now we have to calculate the volume of copper.

Formula used :

Density=\frac{Mass}{Volume}

Now put all the given values in this formula, we get:

8.92\times 10^3kg/m^3=\frac{254g}{Volume}

Volume=\frac{254g}{8.92\times 10^3kg/m^3}=2.85\times 10^{-2}L=2.85\times 10^{-2}\times 10^3cm^3=28.5cm^3

Conversion used :

1kg/m^3=1g/L\\\\1L=10^3cm^3

Therefore, the volume of a sample of 4.00 mol of copper is 28.5cm^3

7 0
3 years ago
Read 2 more answers
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