Refer to the diagram shown below.
T = the tension in the rope
N = the the normal reaction (the force that the table exerts on the box)
W = the hanging weight
Assume that the pulley is frictionless.
For equilibrium,
T = W
and
T + N = 77
Therefore
N = 77 - W
(a) When W = 30 N,
N = 77 - 30 = 47 n
Answer: 47 N
(b) When W = 60 N,
N = 77 - 60 = 17 N
Answer: 17 N
(c) When W = 90 N
N = 77 - 90 = - 13 N
There is no normal reaction, and the system is no longer in equilibrium.
Instead, the box will be lifted by a force of 13 N, and the box will accelerate upward.
Answer:
Here's an explanation but not the answer
Explanation:
When a resistor is traversed in the same direction as the current, the ... Traversing the internal resistance r1 from c to d gives −I2r1. ... I1 = I2 + I3 = (6−2I1) + (22.5− 3I1) = 28.5 − 5I1.
Answer:
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Machine
Subject: Science
Home Grade 9 Science Machine Machine
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Syllabus
Measurement
Force
Machine
Machine
Types of Simple Machine
Moment
Work Energy and Power
Sound
Light
Electricity and Magnetism
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Overview
Simple machine helps us by magnifying force, accelerating work and by changing the direction of force. This notes gives us the information about machine, its importance, mechanical advantage, velocity ratio.
Note
Things to remember
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Exercise
Quiz
Machine
We use various tools to perform different types of work in our daily life. The tools or simple devices used for making our work easier, faster and more convenient are simple machines.
Those tools or devices which make our work easier and convenient in the direction of the force is called simple machine.
Purpose of using simple machine
Simple machines are used to make our work easier in the following ways:
By multiplying force.
By changing the directions of force.
By transferring force from one point to another.
By increasing the rate of doing work.
THIS CAN HELP U
Answer:
Part a: 0.90 J
Part b: 4.5 J
Explanation:
Part a:
The particle of charge q=+8.2 μC will move from x=70cm to x=100cm:
dU=-dK
=(k*q*Q/r_f)-(k*q*Q/r_i)
= -(K_f-K_i)
= (9*10^9)*(8.2*10^-6)*(31*10^-6)/(1)-(9*10^9)*(7.5*10^-6)*(20*10^-6)
= -(K_f-0)
K_f= 0.90 J
Part b: The particle of charge q=+8.2 μC will move from x=70cm to x=20cm:
dU=-dK
=(k*q*Q/r_f)-(k*q*Q/r_i)
= -(K_f-K_i)
= (9*10^9)*(8.2*10^-6)*(-31*10^-6)/(0.2)-(9*10^9)*(7.5*10^-6)*(20*10^-6)
= -(K_f-0)
K_f= 4.5 J
Answer:
Newton's second law
Explanation: hopes this helps
