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3 years ago

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You want to figure out which brand of microwave popcorn pops the most kernels so you can get the most value for your money. You

test different brands of popcorn to see which bag pops the most popcorn kernels. What is the dependent variable?
A. Number of kernels popped
B. The brand of microwave
C. The brand of popcorn
D. The type of popcorn

2 answers:

Kisachek [45]3 years ago

5 0

Answer:

Number of kernels popped

Explanation:

frutty [35]3 years ago

3 0

Answer:

A

Explanation:

I think the number of kernels popped is depended on the brand of the microwave or it can be the brand of popcorn but the independent variable is the cause and the dependent variable is the effect

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An engine draws energy from a hot reservoir with a temperature of 1250 K and exhausts energy into a cold reservoir with a temper

bixtya [17]

Answer:

a. $P=18.61\ W$

b. $\eta_c=0.6976=69.76\%$

c. $\eta=0.4718=47.18\%$

Explanation:

Given:

temperature of the hotter reservoir, $T_H=1250\ K$

temperature of the colder reservoir, $T_C=378\ K$

heat absorbed by the engine, $Q_H=1.42\times 10^{5}\ J$

heat rejected to the cold reservoir, $Q_L=7.5\times 10^4\ J$

time duration of the energy transfer, $t=1\ hr=3600\ s$

<u>Now the work done by the engine:</u>

Using energy conservation,

$W=Q_H-Q_L$

$W=14.2\times 10^4-7.5\times 10^4$

$W=6.7\times 10^4\ J$

a.

<u>Hence the power output:</u>

$P=\frac{W}{t}$

$P=\frac{6.7\times 10^4}{3600}$

$P=18.61\ W$

b.

$\eta_c=1-\frac{T_L}{T_H}$

$\eta_c=1-\frac{378}{1250}$

$\eta_c=0.6976=69.76\%$

c.

now actual efficiency:

$\eta=\frac{W}{Q_H}$

$\eta=\frac{6.7\times 10^4}{1.42\times 10^{5}}$

$\eta=0.4718=47.18\%$

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4 years ago

Consider two transformers. Transformer A has 300 turns on its primary and 500 turns on its secondary. Transformer B has 250 turn

rusak2 [61]

Answer:

Secondary voltage on second transformer is 200 volt.

Explanation:

It is given two transformer

Let us consider first transformer.

Number of turns in primary $N_p=300$

Numb er of turns in secondary $N_s=500$

Now consider second transformer

Number of turns in primary $N_p=250$

Number of turns in secondary $N_s=1000$

Now it is given that same voltage of 50 volt is applied to primary of both the transformer.

For second transformer

$\frac{N_p}{N_s}=\frac{V_p}{V_s}$

$\frac{250}{1000}=\frac{50}{V_s}$

$V_s=200volt$

So secondary voltage on second transformer is 200 volt

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4 years ago

A fan blade is rotating with a constant angular acceleration of 11.5 rad/s2. At what point on the blade, as measured from the ax

vichka [17]

Answer:

Alpha = ω^2 R where R is radius of blade

g = w^2 r where r is distance from center

ω^2 R = 11.5 ω^2 r

R / r = 11.5 / 9.8 = 1.17

Or r = .852 R

Since the angular acceleration depends on both R and ω it seems that one can only get r as it depends on R

7 0

2 years ago

Is F=mxa expressed in equation in newtons second law of motion?

kow [346]

Yes. That equation is exactly how we write Newton's second law nowadays. Note that the 'x' just means 'times'. It's not another variable. The equation could be written as simply. F = m a .

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4 years ago

What does Newton's third law describe?

Dennis_Churaev [7]

A. Equal and opposite forces

Explanation:
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