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Ainat [17]
3 years ago
10

What is a hypothesis?

Chemistry
1 answer:
gladu [14]3 years ago
3 0

Answer: a supposition or proposed explanation made on the basis of limited evidence as a starting point for further investigation.

Explanation: definition

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In Europe, gasoline efficiency is measured in km/L. If your car’s gas mileage is 25.0 mi/gal, how many liters of gasoline would
Deffense [45]

Answer:

V=23.5L

Explanation:

Hello,

In this case, it is convenient to compute the car's mileage in km/L as follows:

25.0\frac{mi}{gal}*\frac{1km}{0.6214mi}*\frac{1gal}{3.78L}=10.64\frac{km}{L}

In such a way, since the distance is measured to be 250 km, the volume requirement is:

V=\frac{250km}{10.64kg/L}\\ \\V=23.5L

Regards.

7 0
3 years ago
What is the density of a liquid if it's volume is 125 mL and it's mass is 50g?
masha68 [24]

Answer:

0.4g/ml

Explanation:

density= mass/volume

density=50g/125ml

density=0.4g/ml

6 0
3 years ago
Write the balanced net reaction for the following half cells: <br> Sn2+ / Sn<br> Cr2+ / Cr
GuDViN [60]

The balanced net reactiion for the following half cells will be

Sn + Cr²⁺   --->  Sn²⁺  +  Cr

<h3>What are Half cells ?</h3>

A half cell is one of the two electrodes of an electrochemical cell.

An electrochemical cell comprises two half cells, where every half cell contains an electrode and an electrolyte.

A salt bridge or direct contact is needed to connect two half cells.

The balanced net reactiion for the given half cells will be

Sn + Cr²⁺   --->  Sn²⁺  +  Cr

Learn more about Half cell here ;

brainly.com/question/1313684

#SPJ1

4 0
2 years ago
Phosphates are formed when phosphorus reacts with
777dan777 [17]

Answer: nitrogen

Explanation: bc

6 0
3 years ago
B. If the sand you ran across has a specific-heat capacity of 835 J/(kgºc),
Murrr4er [49]

Answer: 16700 Joules

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

Q=m\times c\times \Delta T

Q = Heat absorbed = ?

m = mass of sand = 2 kg

c = heat capacity = 835J/kg^0C

Initial temperature  = T_i = 40^0C

Final temperature= T_f  = 50^0C

Change in temperature ,\Delta T=T_f-T_i=(50-40)^0C=10^0C

Putting in the values, we get:

Q=2kg\times 835J/kg^0C\times 10^0C

Q=16700J

16700 J of energy must be added to a 2-kilogram pile of it to increase its temperature from 40°C to 50°C

4 0
3 years ago
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