The left side equals the right side, so it has infinitely many solutions.
Answer:
c.k¹¹
Step-by-step explanation:
Anything raised to the power of 0 is one so k^0=1
k^4k^7
Since they have the same base you can just add them
4+7=11
8x(5x2+3)=8x(15+3)=8x13=104
Answer:
x ≤ -5
Step-by-step explanation:
According to given condition:
3x + 17 ≤ 2(1 - x)
By simplifying:
3x + 17 ≤ 2 - 2x
Adding 2x - 17 on both sides we get:
3x + 2x ≤ 2 - 17
5x ≤ - 15
Dividing both sides by 5 we get:
x ≤ -5
i hope it will help you!
Answer:
First let's define what modular arithmetic is, what would come is an arithmetic system for equivalence classes of whole numbers called congruence classes.
Now, the modular division is the division in modular arithmetic.
Answering the question, a modular division problem like ordinary arithmetic is not used, division by 0 is undefined. For example, 6/0 is not allowed. In modular arithmetic, not only 6/0 is not allowed, but 6/12 under module 6 is also not allowed. The reason is that 12 is congruent with 0 when the module is 6.
