Answer: The common number is 26.
Step-by-step explanation:
We know that the n-th term of a sequence is:
aₙ = 3*n^2 - 1
And the n-th term of another sequence is:
bₙ = 30 - n^2
Remember that in a sequence n is always an integer number.
We want to find a number that belongs to both sequences, then we want to find a pair of integers x and n, such that:
aₙ = bₓ
This is:
3*n^2 - 1 = 30 - x^2
Let's isolate one of the variables, i will isolate n.
3*n^2 = 30 - x^2 + 1 = 31 - x^2
n^2 = (31 - x^2)/3
n = √( (31 - x^2)/3)
Now we can try with different integer values of x, and see if n is also an integer.
if x = 1
n = √( (31 - 1^2)/3) = √10
We know that √10 is not an integer, so we need to try with another value of x.
if x = 2:
n = √( (31 - x^2)/3) = √(27/3) = √9 = 3
Then if we have x= 2, n is also an integer, n = 3.
Then we have:
a₃ = b₂
The common number between both sequences is:
a₃ = 3*(3)^2 - 1 = 26
b₂ = 30 - 2^2 = 26
Answer:
Actually the answer is "A"
this is a very strange way to present a problem...
this issue her is that 
so you need 1/3 * 3 in the answer... none of them have 1/3 * 3
BUT !!!!! 1/3 + 1/3 + 1/3 is the same as 1/3 * 3 So "A" is the solution
Step-by-step explanation:
X + y = 4200 so x = 4200 - y
0.035x + 0.045y = 174
substitute x = 4200 - y into 0.035x + 0.045y = 174
0.035x + 0.045y = 174
0.035(4200 - y) + 0.045y = 174
147 - 0.035y + 0.045y = 174
0.01y = 27
y = 2700
x + y = 4200
x = 4200 - 2700
x = 1500
answer
$1500 in <span>3.5%
$2700 in 4.5%</span>
