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Blizzard [7]
3 years ago
6

Can you all please help me with problems 6 through 10? Please don’t use for points I’m extremely stressed and need help

Mathematics
2 answers:
patriot [66]3 years ago
5 0

Answer:

See below.

Step-by-step explanation:

6.) (5)/6 ≤ 1 (Yes)

7.) 1.4(11) > 16

    15.4 > 16 (No)

8.) 11.1 + 9.8 ≥ 21.01

    20.9 ≥ 21.01 (No)

9.) 2.5 < (90)/30

    2.5 < 3 (Yes)

10.) 1/2 > 3(1/6)

      1/2 > 1/2 (No)

11.) 2.16 ≥ 3(0.6) - 0.5

     2.16 ≥ 1.8 - 0.5

     2.16 ≥ 1.3 (Yes)

12.) x < 2 (x is less than 2.)

13.) x ≥ -1 (x is greater than or equal to -1.)

lutik1710 [3]3 years ago
5 0
1.yes
2.no
3.no
4.yes
5.no
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Which of the following coordinates is a solution to the linear equation?
Dima020 [189]
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7 0
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Find the derivative of
kirill [66]

Answer:

\displaystyle y'(1, \frac{3}{2}) = -3

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Coordinates (x, y)
  • Functions
  • Function Notation
  • Terms/Coefficients
  • Exponential Rule [Rewrite]:                                                                              \displaystyle b^{-m} = \frac{1}{b^m}

<u>Calculus</u>

Derivatives

Derivative Notation

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Step-by-step explanation:

<u>Step 1: Define</u>

<u />\displaystyle y = \frac{3}{2x^2}<u />

\displaystyle \text{Point} \ (1, \frac{3}{2})

<u>Step 2: Differentiate</u>

  1. [Function] Rewrite [Exponential Rule - Rewrite]:                                            \displaystyle y = \frac{3}{2}x^{-2}
  2. Basic Power Rule:                                                                                             \displaystyle y' = -2 \cdot \frac{3}{2}x^{-2 - 1}
  3. Simplify:                                                                                                             \displaystyle y' = -3x^{-3}
  4. Rewrite [Exponential Rule - Rewrite]:                                                              \displaystyle y' = \frac{-3}{x^3}

<u>Step 3: Solve</u>

  1. Substitute in coordinate [Derivative]:                                                              \displaystyle y'(1, \frac{3}{2}) = \frac{-3}{1^3}
  2. Evaluate exponents:                                                                                         \displaystyle y'(1, \frac{3}{2}) = \frac{-3}{1}
  3. Divide:                                                                                                               \displaystyle y'(1, \frac{3}{2}) = -3

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Derivatives

Book: College Calculus 10e

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