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svet-max [94.6K]
3 years ago
12

To locate all the documents in a Mongo database that match an expression, use the _____________ method.

Computers and Technology
1 answer:
Lena [83]3 years ago
4 0

Answer:

find()

Explanation:

When dealing with MongoDB the method that needs to be used in this scenario would be the find() method. This method basically returns all of the records that exist in the collection on which it is called, if no parameter is passed. If you pass a parameter/expression then only the records that match completely the expression will be returned to the user, otherwise nothing is returned. For example, on a database (db) we would call the following

db.find() ... This will return all records

db.find({specific}) ... This will return only the records that match specific.

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In mathematics, "quadrant I" of the cartesian plane is the part of the plane where x and y are both positive. Given a variable,
lbvjy [14]

Answer:

#include <iostream>

using namespace std;

struct Cartesian {

double x;

double y;

};

int main() {

// creating a pointer p of type struct Cartesian

struct Cartesian *p = new Cartesian ;

cout << " Enter x: ";

// accessing the structure variable x by arrow "->"

cin >> p->x;

cout << "Enter y: ";

// accessing the structure variable y by arrow "->"

cin >> p->y;

// expression to check whether x and y lie in Quadrant 1

if (p->x > 0 && p->y > 0) {

 cout << "X and Y are in Quadrant 1 ";

}

else

{

 cout << "x And y are not in Quadrant 1";

}

// deleting the struct pointer p

delete p;

return 0;

}

Explanation:

in order to locate memory in heap, keyword "new" is used in C++ so,

struct Cartesian *p = new Cartesian ;

in order to access data members of the structure using pointer we always use an arrow "->". otherwise a dot oprerator is used to access data members.

in order to check whether x and y lie in 1st quadrent, we must use && operator in our if condition. so

if (p->x > 0 && p->y > 0)

&& will return true iff x and y both are +ve.

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delete p;

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Answer:

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