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3 years ago

Question 9 Water molecules require a lot of energy to separate them because...

Chemistry

2 answers:

valentina_108 [34]3 years ago

8 0

A

is the answer
just bc

ira [324]3 years ago

3 0

Answer:

they are highly adhesive

Explanation:

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Which of the following is a correct formula unit of an ionic compound?

goldenfox [79]

Answer : The correct formula unit of an ionic compound is Ca(OH)2

Explanation :

An ionic compound is formed when a metal atom donates one or more electrons to a non metal atom.

During this process, metal gains a positive charge and a nonmetal gets a negative charge.

In an ionic compound, these charges on the ions are balanced so that the overall compound is neutral.

Let us check which of the given compounds have a neutral charge.

1) Al2F3 : Charge on Al is +3 and that on F is -1.

The total charge on 2 Al is 2x3 = +6.

The total charge on 3 F atoms is 3x(-1) = -3

The overall charge on the compound is +6-3 = +3.

That means the given formula unit is not correct.

2) Ca2O : Charge on Ca is +2 and that on O is -2

Total charge on Ca is 2x2 = +4

The overall charge is +4-2 = +2

Therefore the given formula unit is not correct.

3) Ca(OH)2 : The charge on Ca ion is +2 and that on OH is -1.

The total charge on 2 OH ions is 2x(-1) = -2

The overall charge is +2-2 = 0

This gives a neutral compound.

Therefore the given formula unit is correct.

6 0

4 years ago

Read 2 more answers

The transfer of energy that occurs when a force is applied over a distance is

nika2105 [10]

The transfer of energy that occurs when a force is applied over a distance is WORK.

Hope this helps!

3 0

3 years ago

Draw the mechanism for the addition of methylmagnesium bromide to propanoyl chloride (CH3CH2COCl) to give 2-methyl-2-butanol.

Ghella [55]

Answer:

Reaction mechanism has been given below

Explanation:

Propanoyl chloride contains an electrophilic carbonyl center to give nucleophilic acyl substitution reaction by removing Cl group with a strong nucleophile like methylmagnesium bromide.
Two equivalent of methyl magnesium bromide react with cabonyl center followed by protonation of negatively charged oxygen atom gives 2-methyl-2-butanol.
In the first step, nucleophilic acyl substituion occurs. In the second step, nucleophilic addition occurs. In the third step, protonation occurs.
Reaction mechanism has been shown below.

7 0

3 years ago

What is the mass of 1 mole of lithium?

Korolek [52]

<u>Answer:</u> The mass of 1 mole of lithium is 6.941 grams.

<u>Explanation:</u>

To calculate the mass of a compound or element, we use the formula used to calculate the number of moles:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Where,

Number of moles of lithium = 1 mole

Given mass of lithium = ? g

Molar mass of lithium = 6.941 g/mol

Putting value in above equation, we get:

$1mole=\frac{\text{Given mass}}{6.941g/mol}\\\\\text{Mass of lithium}=6.941g$

Hence, the mass of 1 mole of lithium is 6.941 grams.

5 0

3 years ago

Read 2 more answers

How much energy must be added to a 1 kg piece of gold with a specific heat of 130 j/kg to increase its temperature from 20 c to

Lorico [155]

$Q = 10.4 \; \text{kJ}$

The specific heat of a material gives the energy it takes to increase the temperature of one unit mass of the material by one unit temperature. The SI unit for specific heat $c$ is therefore $\text{J} /\text{kg} \cdot \textdegree{\text{C}}$ .

The formula relating the energy required to raise the temperature of $m$ grams of a substance with specific energy $c$ by $\Delta T$ degrees is

$Q= c \cdot m \cdot \Delta T$

The question provides the following information:

$c = 130\; \text{J} /\text{kg} \cdot \textdegree{\text{C}}$ for gold
$m= 1 \; \text{kg}$
$\Delta T = 100 \textdegree{\text{C}} - 20 \textdegree{\text{C}} = 80 \textdegree{\text{C}}$

Apply the formula:

$\begin{array}{ccc} Q & = & c \cdot m \cdot \Delta T\\ & = & 130 \; \text{J} \cdot \text{kg}^{-1} \cdot \textdegree{\text{C}}^{-1} \times 1 \; \text{kg} \times 80 \; \textdegree{\text{C}}\\ & = & 1.04 \times 10^{4} \;\text{J}\\ & = & 10.4 \; \text {kJ} \end{array}$

7 0

4 years ago