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Serhud [2]
4 years ago
11

Which of the following is a correct formula unit of an ionic compound?

Chemistry
2 answers:
goldenfox [79]4 years ago
6 0

Answer : The correct formula unit of an ionic compound is Ca(OH)2

Explanation :

An ionic compound is formed when a metal atom donates one or more electrons to a non metal atom.

During this process, metal gains a positive charge and a nonmetal gets a negative charge.

In an ionic compound, these charges on the ions are balanced so that the overall compound is neutral.

Let us check which of the given compounds have a neutral charge.

1) Al2F3 : Charge on Al is +3 and that on F is -1.

The total charge on 2 Al is 2x3 = +6.

The total charge on 3 F atoms is 3x(-1) = -3

The overall charge on the compound is +6-3 = +3.

That means the given formula unit is not correct.

2) Ca2O : Charge on Ca is +2 and that on O is -2

Total charge on Ca is 2x2 = +4

The overall charge is +4-2 = +2

Therefore the given formula unit is not correct.

3) Ca(OH)2 : The charge on Ca ion is +2 and that on OH is -1.

The total charge on 2 OH ions is 2x(-1) = -2

The overall charge is +2-2 = 0

This gives a neutral compound.

Therefore the given formula unit is correct.


scoray [572]4 years ago
4 0

The answer is C)

Ca(OH)2

I took the test and it was correct

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What is relative dating? A. the process of determining the order of events in geologic time B.process of determining a specific
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3 years ago
Be sure to answer all parts. Calculate the pH of the following two buffer solutions: (a) 1.4 M CH3COONa/1.6 M CH3COOH. (b) 0.1 M
aalyn [17]

Answer:

a) pH = 4.68 (more effective)

b) pH =4.44.

Explanation:

The pH of buffer solution is obtained by Henderson Hassalbalch's equation.

The equation is:

pH =pKa +log\frac{[salt]}{[acid]}

a) pKa of acetic acid = 4.74

[salt] = [CH₃COONa] = 1.4 M

[acid] = [CH₃COOH] = 1.6 M

pH = 4.74 + log \frac{1.4}{1.6}= 4.68

This is more effective as there is very less difference in the concentration of salt and acid.

b) pKa of acetic acid = 4.74

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[acid] = [CH₃COOH] = 0.2 M

pH = 4.74 + log \frac{0.1}{0.2}= 4.44

3 0
3 years ago
How many moles of hydrogen gas will be produced if 5.00 moles of zinc reactions with an excess amount of sulfuric acid
harkovskaia [24]

Answer:

Moles of Hydrogen produced is 5 moles

Explanation:

The balanced Chemical equation for reaction between zinc and sulfuric acid is :

Zn(s) + H_{2}SO_{4}(aq) \rightarrow ZnSO_{4}(aq) + H_{2}(g)

This equation tells that ; when  1 mole of Zn react with 1 mole of sulfuric acid, it produces 1 mole of zinc sulfate and 1 mole of hydrogen.

Since sulfuric acid is in excess so Zinc is the limiting reagent

(Limiting reagent : Substance which get consumed when the reaction completes, limiting reagent helps in predicting the amount of products formed)

Limiting reagent (Zn) will decide the amount of Hydrogen produced

Zn(s) + H_{2}SO_{4}(aq) \rightarrow ZnSO_{4}(aq) + H_{2}(g)

1\ mole\ zinc\rightarrow 1\ mole\ H_{2}

So,

5\ mole\ zinc\rightarrow 5\ mole\ H_{2}

Hence moles of Hydrogen produced is 5 moles

3 0
3 years ago
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