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Serhud [2]
4 years ago
11

Which of the following is a correct formula unit of an ionic compound?

Chemistry
2 answers:
goldenfox [79]4 years ago
6 0

Answer : The correct formula unit of an ionic compound is Ca(OH)2

Explanation :

An ionic compound is formed when a metal atom donates one or more electrons to a non metal atom.

During this process, metal gains a positive charge and a nonmetal gets a negative charge.

In an ionic compound, these charges on the ions are balanced so that the overall compound is neutral.

Let us check which of the given compounds have a neutral charge.

1) Al2F3 : Charge on Al is +3 and that on F is -1.

The total charge on 2 Al is 2x3 = +6.

The total charge on 3 F atoms is 3x(-1) = -3

The overall charge on the compound is +6-3 = +3.

That means the given formula unit is not correct.

2) Ca2O : Charge on Ca is +2 and that on O is -2

Total charge on Ca is 2x2 = +4

The overall charge is +4-2 = +2

Therefore the given formula unit is not correct.

3) Ca(OH)2 : The charge on Ca ion is +2 and that on OH is -1.

The total charge on 2 OH ions is 2x(-1) = -2

The overall charge is +2-2 = 0

This gives a neutral compound.

Therefore the given formula unit is correct.


scoray [572]4 years ago
4 0

The answer is C)

Ca(OH)2

I took the test and it was correct

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Calculate the molar solubility of PbCO3 when the Ksp of PbCO3 is 1.5*10^-15 at 25°C.
sertanlavr [38]
First, write the dissociation equation for PbCO3 which is PbCO3 = Pb^(2+) + CO3^(2-). Then, write the Ksp equation which is Ksp = [Pb^(2+)][CO3^(2-)]. The equation suggests that there is 1:1 molar ratio between the Pb^(2+), CO3^(2-) and the dissolved PbCO3. Thus in equation form, we can represent them as x. The Ksp equation is then: 1.5*10^-15 = x^2. The molar solubility of PbCO3, x, is then equal to 3.87*10^-8 moles per liter.
7 0
3 years ago
Calcium cyanamide, CaCN2, reacts with water to form calcium carbonate and ammonia. CaCN2(s)+3H2O(l)→CaCO3(s)+2NH3(g). How many g
Norma-Jean [14]

298 g of calcium carbonate CaCO₃

Explanation:

We have the following chemical reaction:

CaCN₂ (s) + 3 H₂O (l) → CaCO₃ (s)+ 2 NH₃ (g)

number of moles = mass / molar weight

number of moles of H₂O = 161 / 18 = 8.94 moles

Knowing the chemical reaction we devise the following reasoning:

if        3 moles of H₂O produces 1 mole of CaCO₃

then  8.94 moles of H₂O produces X moles of CaCO₃

X = (8.94 × 1) / 3 = 2.98 moles of CaCO₃

mass =  number of moles × molar weight

mass of CaCO₃ = 2.98 × 100 = 298 g

Learn more about:

number of moles

brainly.com/question/1445383

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7 0
3 years ago
How to economically produce fine greens
nika2105 [10]

Answer:

A transition to renewable energy and to replace fossil fuels would take care of economically producing fine greens. Also, a transition to energy conservation and efficient energy use would help in this process.

Have a great day!

5 0
3 years ago
4th one<br> Mark the brainliest
ale4655 [162]

Answer:

1. The electronic configuration of X is: 1s2 2s2 sp6 3s2

2. The configuration of the anion of Y (i.e Y^2-) is 1s2 2s2 2p6

3. The formula of the compound form by X and Y is given as: XY

Explanation:

For X to loss two electrons, it means X is a group 2 element. X can be any element in group 2. The electronic configuration of X is:

1s2 2s2 sp6 3s2

To get the electronic configuration of the anion of element Y, let us find the configuration of element Y. This is done as follows:

Y receives two electrons from X to complete its octet. Therefore Y is a group 6 element. The electronic configuration of Y is given below

1s2 2s2 2p4

The configuration of the anion of Y (i.e Y^2-) is 1s2 2s2 2p6

The formula of the compound form by X and Y is given below :

X^2+ + Y^2- —> XY

Their valency will cancel out thus forming XY

4 0
4 years ago
The concentration of an HCl acid solution is initially 6mol/L. What would the concentration of a new solution be if 200 mL of th
pochemuha

Taking into account the definition of dilution, the concentration of the new solution is 1 mol/L.

<h3>Dilution</h3>

When it is desired to prepare a less concentrated solution from a more concentrated one, it is called dilution.

Dilution is the process of reducing the concentration of solute in solution, which is accomplished by simply adding more solvent to the solution at the same amount of solute.

In a dilution the amount of solute does not change, but as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.

A dilution is mathematically expressed as:

Ci×Vi = Cf×Vf

where

  • Ci: initial concentration
  • Vi: initial volume
  • Cf: final concentration
  • Vf: final volume

<h3>Final volume</h3>

In this case, you know:

  • Ci= 6 mol/L
  • Vi= 200 mL
  • Cf= ?
  • Vf= 1 L (1000 mL) water + 200 mL of HCL= 1200 mL

Replacing in the definition of dilution:

6 mol/L× 200 mL= Cf× 1200 mL

Solving:

(6 mol/L× 200 mL)÷ 1200 mL= Cf

<u><em>1 mol/L= Cf</em></u>

In summary, the concentration of the new solution is 1 mol/L.

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