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Mice21 [21]
3 years ago
15

If the pressure on a gas sample is tripled and the absolute temperature is quadrupled, by what factor will the volume of the sam

ple change?
a.12

b.4/3

c.3/4

d.1/3

e.4
Chemistry
1 answer:
antoniya [11.8K]3 years ago
7 0

Answer:

b. 4/3

Explanation:

Given data

  • Initial pressure: P₁
  • Initial volume: V₁
  • Initial temperature: T₁
  • Final pressure: P₂ = 3 P₁
  • Final volume: V₂
  • Final temperature: T₂ = 4 T₁

We can find by what factor will the volume of the sample change using the combined gas law.

\frac{P_{1}.V_{1}}{T_{1}} =\frac{P_{2}.V_{2}}{T_{2}}\\\frac{P_{1}.V_{1}}{T_{1}} =\frac{3P_{1}.V_{2}}{4T_{1}}\\V_{1} =\frac{3V_{2}}{4}\\V_{2}=4/3 V_{1}

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1
larisa [96]

Answer:

group I: alkali metals

group II (beryllium to radium): alkaline earth metals

group II (scandium to zinc , yttrium to cadmium, lanthanoid series to mercury, actinoid series to copernicium): transition metals

group VII (fluorine to astatine): halogens

group VIII: (helium to radon): noble gases

Explanation:

3 0
3 years ago
What In the formula Na3PO4 how many moles of sodium? How many moles of phosphorus? How many moles of oxygen?
yulyashka [42]
Sodium is Na, so there's 3 moles of that. Phosphorus is P, there's 1 mole of that. Oxygen is O, there's 4 moles of that.
5 0
3 years ago
If the density of pure water is 0.9922 g/mL at 40 ºC, calculate its theoretical molarity at that temperature. Report to 4 sig fi
OleMash [197]
Answer is: theoretical molarity of water is 55.1222 mol/L.<span>
d(H</span>₂O) = 0.9922 g/mL.
M(H₂O) = 2 · Ar(H) + Ar(O) · g/mol.
M(H₂O) = 2 + 16 · g/mol = 18 g/mol.
c(H₂O) = d(H₂O) ÷ M(H₂O).
c(H₂O) = 0.9922 g/mL ÷ 18 g/mol.
c(H₂O) = 0.0551 mol/mL.
c(H₂O) = 0.0551 mol/mL · 1000 mL/L = 55.1222 mol/L.
3 0
4 years ago
What Is a decrease in velocity called
Andrews [41]
The decrease in velocity is called deceleration or negative acceleration.


Hope i helped... If you need anything else ask me! :)

5 0
3 years ago
A block made of a certain material has a thickness of 20 cm and a thermal conductivity of 0.04 m C. At a particular instant in t
amid [387]

Answer:

heat flux ( Q ) = 8 W/m³ uniform heat flux throughout the block

Explanation:

flat plate ecuation with uniform source:

  • d2T / dx² = - Q / k...........from general balance
  • if x = 0 ⇒ dT / dx = 0 ; Q = 0
  • if x = L ⇒ T = T1

∴ k = 0.04 W/mC;   L = 0.2 m

If T = - 100x² + 20x

⇒ dT / dx = - 200x + 20

⇒ d2T / dx² = - 200 = - Q / k

⇒ Q / k = 200

⇒ Q = 200 * 0.04 W/mC

⇒ Q = 8 W/m³

8 0
4 years ago
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