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VLD [36.1K]
3 years ago
9

The number of positive changes in the nucleus of an atom is equal to

Chemistry
1 answer:
raketka [301]3 years ago
8 0

Answer:

The number of positive charges in nucleus of an atoms are equal to the atomic number and also positive charges are equal to the negative charges which are electrons in neutral atom.

Explanation:

An atom consist of electron, protons and neutrons. Protons and neutrons are present with in nucleus while the electrons are present out side the nucleus.

Electron:

The electron is subatomic particle that revolve around outside the nucleus and has negligible mass. It has a negative charge.

Symbol= e⁻

Mass= 9.10938356×10⁻³¹ Kg

It was discovered by j. j. Thomson in 1897 during the study of cathode ray properties.

Neutron and proton:

Neutron and proton are present inside the nucleus. Proton has positive charge while neutron is electrically neutral. Proton is discovered by Rutherford while neutron is discovered by James Chadwick in 1932.

Symbol of proton= P⁺

Symbol of neutron= n⁰

Mass of proton=1.672623×10⁻²⁷ Kg

Mass of neutron=1.674929×10⁻²⁷ Kg

All these three subatomic particles construct an atom. A neutral atom have equal number of proton and electron. In other words we can say that negative and positive charges are equal in magnitude and cancel the each other. For example if neutral atom has 6 protons than it must have 6 electrons. The sum of neutrons and protons is the mass number of an atom while the number of protons are number of electrons is the atomic number of an atom.

For example

The carbon have six protons and six neutrons so its atomic mass is 12 amu and atomic number is six.

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CF4 + Br2 CBr4 + F2
luda_lava [24]

Answer:

Answers are in the explanation

Explanation:

Based on the reaction:

CF₄ + 2Br₂ → CBr₄ + 2F₂

The mole ratio of CF₄ is:

CF₄:Br₂ = 1:2

CF₄:CBr₄ = 1:1

CF₄:F₂ = 1:2

<em>Moles F2:</em>

Molar mass CF₄: 88.0g/mol

57.0g * (1mol / 88.0g) = 0.6477 moles CF₄ * (2mol F₂ / 1mol CBr₄) =

<h3>1.30 moles F₂</h3><h3 />

<em>Mass Br2:</em>

Molar mass CBr₄: 331.63g/mol

250.0g * (1mol / 331.63g) = 0.7539 moles CBr₄ * (2mol Br₂ / 1mol CF₄) =

1.51 moles Br₂ * (159.808g / mol) =

<h3>241g Br2</h3><h3 /><h3 />

<em>Moles F2:</em>

4.8 moles CF₄ * (2mol F₂ / 1mol CF₄) =

<h3>9.6 moles F₂</h3><h3 />

<em />

5 0
3 years ago
In a classical long run supply model the economy is always doing what
ch4aika [34]

Answer:

Economy is always at the full employment level of output

Explanation:

The economy in a classical long-run supply model will always have the same economic output

8 0
3 years ago
How many moles of glucose (C6H12O6) are in 5.0 liters of a 2.5 M C6H12O6 solution?
zhannawk [14.2K]
N = M x V      

n = 2.5 x 5.0
 
n = 12.5 moles of C6H12O6
5 0
3 years ago
The volume (in L) that would be occupied by 5.00 mols of 02 at STP is
crimeas [40]

Answer : The volume of oxygen at STP is 112.0665 L

Solution : Given,

The number of moles of O_2 = 5 moles

At STP, the temperature is 273 K and pressure is 1 atm.

Using ideal gas law equation :

PV=nRT

where,

P = pressure of gas

V = volume of gas

n = the number of moles

T = temperature of gas

R = gas constant = 0.0821 L atm/mole K   (Given)

By rearranging the above ideal gas law equation, we get

V=\frac{nRT}{P}

Now put all the given values in this expression, we get the value of volume.

V=\frac{(5moles)\times (0.0821Latm/moleK)\times (273K)}{1atm}=112.0665L

Therefore, the volume of oxygen at STP is 112.0665 L

3 0
3 years ago
1. I am a solution with a pOH of 6. What am I?
ivolga24 [154]

Explanation:

I think 1) acidic solution

2) basic solution.

8 0
3 years ago
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