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Levart [38]
3 years ago
9

5. What is the second step in proving by mathematical induction that for every positive integer n, 11" - 6 is divisible by

Mathematics
2 answers:
WARRIOR [948]3 years ago
4 0

Answer:

Step-by-step explanation:

Premise:  If n is a positive integer, then 11ⁿ-6 is divisible by 5.

Let n=1.

11¹-6 = 5, so the premise is true for n=1.

Suppose the premise is true when n is an integer greater than 1,

then 11ⁿ-6 is divisible by 5.

11ⁿ⁺¹-6 = 11·11ⁿ - 6

   = (10+1)11ⁿ - 6

   = (10·11ⁿ) + (1·11ⁿ) - 6

   = (10·11ⁿ) + (11ⁿ - 6)

Both terms are divisible by 5, so 11ⁿ⁺¹-6 is divisible by 5. Therefore, the premise holds true for n+1.

Proof by induction.

astraxan [27]3 years ago
3 0

Answer:

The correct answer is A:Let n = k. Then assume that 11" - 6 is divisible by 5. sorry if im wrong but if correct pls mark brainliest

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