We want to get the expected value for the given experiment. We will see that the expected value is $2.33
For an experiment with outcomes {x₁, ..., xₙ} each one with probability {p₁, ..., pₙ} the expected value is defined as:
EV = x₁*p₁ + ... + xₙ*pₙ
Here we have 3 outcomes:
- x₁ = winning $8
- x₂ = winning $2
- x₃ = winning $0.
For x₁ we need to roll a 6, this is a probability of 1 out of 6, then:
p₁ = 1/6
For x₂ we need to roll a 3, 4, or 5 (3 out of 6), then:
p₂ = 3/6
For x₃ we need to roll a 1 or a 2 (2 out of 6) so the probability is:
p₃ = 2/6
Then the expected value is:
EV = $8*(1/6) + $2*(3/6) + $0*(2/6) = $2.33
If you want to learn more about expected values, you can read:
brainly.com/question/15858152
Answer:
Step-by-step explanation:
See the picture attached to better understand the problem
we know that
If two secant segments are drawn to a <span>circle </span><span>from an exterior point, then the product of the measures of one secant segment and its external secant segment is equal to the product of the measures of the other secant segment and its external secant segment.
</span>so
jl*jk=jn*jm------> jn=jl*jk/jm
we have
<span>jk=8,lk=4 and jm=6
</span>jl=8+4----> 12
jn=jl*jk/jm-----> jn=12*8/6----> jn=16
the answer isjn=16
This is easy all you have to do is use the formula of the volume which is v=l.h.w
(X+9)(x+4)(x+5)= v
(X+9)(x^2+9x+20)
X^3+18x^2+101x+180=v
Ellen bought soccer shorts on sale for $6 off the regular price of $40. What Percent did she save?
The answer is 15%