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mixas84 [53]
2 years ago
9

What is one over six plus three over six?

Mathematics
1 answer:
IrinaK [193]2 years ago
8 0

Answer:4 over 6

Step-by-step explanation:since both denominators are 6, the denominator stays the same. so all you have to do is add 1 and 3. You can also round to 2 over 3.

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for what values of a, a polynomial in standard form, equivalent to the product of (x^2+x-1)(x-a), does not contain x^2
xeze [42]

Answer:

a = 1

Step-by-step explanation:

(x²+x-1)(x-1) = x³+x²-x-x²-x+1 = x³-2x+1

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3 years ago
Write the equation of the line, with the given properties, in the slope-intercept form.Slope= -3, through (-9,7)
MatroZZZ [7]

The equation of a line in point slope form is;

he

7 0
1 year ago
Find the value of the following.<br> (a) 180 % of 200g
Natasha_Volkova [10]

Answer:

\frac{180| }{100}  \times 200 = 360

3 0
3 years ago
Read 2 more answers
53w+13 is less than 56w+16
Klio2033 [76]

Answer:

inequality form: w<-1

interval notation: (-1)

if this is not what your looking for then this might help

53w+13<55w+16

get w to one side

subtract 53w from both sides

13<3w+16

get 3w by itself

subtract 16 from both sides

-3<3w

divided both side by 3 to solve for w

-1<w

or w>-1

i hope this helped

and if it helped plzzzz mark as brainlest im trying to level up thanks

3 0
3 years ago
Read 2 more answers
PLEASEEE EXPLAIN AND HELP
Firdavs [7]

The length of the unknown sides of the triangles are as follows:

CD = 10√2

AC = 10√2

BC =  10

AB = 10

<h3>Triangle ACD</h3>

ΔACD is a right angle triangle. Therefore, Pythagoras theorem can be used to find the sides of the triangle.

  • c² = a² + b²

where

c = hypotenuse side = AD = 20

a and b are the other 2 legs

lets use trigonometric ratio to find CD,

cos 45 = adjacent / hypotenuse

cos 45 = CD / 20

CD = 1 / √2 × 20

CD = 20 / √2 = 20√2 / 2 = 10√2

20² - (10√2)² = AC²

400 - 100(2)  = AC²

AC² = 200

AC = √200 = 10√2

<h3>Triangle ABC</h3>

ΔABC is a right angle triangle too. Therefore,

  • AB² + BC² = AC²

Using trigonometric ratio,

cos 45 = BC / 10√2

BC = 10√2 × cos 45

BC = 10√2 × 1 / √2

BC = 10√2 / √2 =  10

(10√2)² - 10² = AB²

200 - 100 = AB²

AB² = 100

AB = 10

learn more on triangles here: brainly.com/question/24304623?referrer=searchResults

5 0
2 years ago
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