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Softa [21]
2 years ago
15

What type of testing can reveal the precense of blood?

Chemistry
1 answer:
lorasvet [3.4K]2 years ago
3 0

Answer: precipitin test

Explanation:

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What may happen to the human body when exposed to an infectious agent?
Hatshy [7]

Answer:

When the body is exposed to viruses, bacteria, fungi, or parasites through an infection or vaccination the immune system creates antibodies and immune cells that inactivate or destroy the specific infectious organism.

Explanation:

hope this helps :D

3 0
3 years ago
I need help on 5,6,7. I would give you guys a thank you. This is going to be due very soon.
Ira Lisetskai [31]

Answer:

5) Plant; 6) Heat; 7) never heard of chemosynthesis, sorry :(

Explanation:

A plant is the only thing in an ecosystem that uses photosyenthesis. This includes trees, algea, and grass.

80% of energy is lost as heat used in order to keep the animal warm.

I am really sorry I couldn’t help with 7!

3 0
3 years ago
The reaction between ethylene and hydrogen bromide to form ethyl bromide is carried out in a continuous reactor. The product str
iren2701 [21]

Answer:

Explanation:

The first thing to do is to write out the chemical equation showing the reaction between the two chemical compounds.

C2H4 + HBr ------------------------> C2H5Br.

The chemical species/compounds reacted in the ratio of 1 : 1 : 1. That is one mole of C2H4 reacted with one mole of HBr to give one mole of C2H5Br.

So, we are given; C2H5Br = 58.7 mol%, HBr = 18.3 mol%. Thus, for C2H4, we have [ 100 - (58.7 + 18.3)] = 23 mol%. Therefore, the limiting reagent is HBr.

So, if we have 100 mol/s ;

C2H5Br = 100 × 0.587 = 58.7 mol/s, HBr = 100 × 0.183 = 18.3 mol/s and C2H4 = 100 × 0.23 = 23 mol/s.

Therefore, the total value of the flow rate in the feed = (HBr in feed) mol/s + (C2H4 in feed) mol/s = (58.7 + 18.3)mol/s + (58.7 + 23) mol/s =( 77 + 81.7) mol/s = 158.7 mol/s. .

So, 100/158.7 × 30.5 = 192.2.

Also the feed composition in HBr and C2H4 is;

HBr = 77/158.7 = 0.4852, C2H4 = 81.7/158.7 = 0.515.

Therefore, the number of HBr in feed and C2H4 in feed = 160m/s and 200m/s respectively (approx.)

Therefore, the fraction conversion is;

8 0
3 years ago
A student constructs a coffee cup calorimeter and places 50.0 mL of water into it. After a brief period of stabilization, the te
Grace [21]

Answer:

The calorimeter constant is  = 447 J/°C

Explanation:

The heat absorbed or released (Q) by water can be calculated with the following expression:

Q = c × m × ΔT

where,

c is the specific heat

m is the mass

ΔT is the change in temperature

The water that is initially in the calorimeter (w₁) absorbs heat while the water that is added (w₂) later releases heat. The calorimeter also absorbs heat.

The heat absorbed by the calorimeter (Q) can be calculated with the following expression:

Q = C × ΔT

where,

C is the calorimeter constant

The density of water is 1.00 g/mL so 50.0 mL = 50.0 g. The sum of the heat absorbed and the heat released is equal to zero (conservation of energy).

Qabs + Qrel = 0

Qabs = - Qrel

Qcal + Qw₁ = - Qw₂

Qcal = - (Qw₂ + Qw₁)

Ccal . ΔTcal = - (cw . mw₁ . ΔTw₁ + cw . mw₂ . ΔTw₂)

Ccal . (30.31°C - 22.6°C) = - [(4.184 J/g.°C) × 50.0 g × (30.31°C - 22.6°C) +  (4.184 J/g.°C) × 50.0 g × (30.31°C - 54.5°C)]

Ccal  = 447 J/°C

5 0
3 years ago
I dunno which one it is could someone help please?​
alex41 [277]

Answer: B. photosynthesis

Explanation: Glucose and oxygen react together in plant cells to produce energy.

5 0
3 years ago
Read 2 more answers
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