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quester [9]
2 years ago
10

A chemist prepares a solution of copper(II) sulfate CuSO4 by measuring out 31.μmol of copper(II) sulfate into a 150.mL volumetri

c flask and filling the flask to the mark with water.
Required:
Calculate the concentration in mol/L of the chemist's copper(II) sulfate solution.
Chemistry
1 answer:
baherus [9]2 years ago
3 0

Answer:

The concentration of the copper (II) sulfate solution is 2.06 * 10^2 μmol/L or 2.06 * 10^2 μM

Explanation:

The concentration of a solution is the amount of solute dissolved in a given volume of solution. In this case, the concentration of the copper(II) sulfate solution in micromoles per liter (symbol ) is the number of micromoles of copper(II) sulfate dissolved in each liter of solution. To calculate the micromoles of copper(II) sulfate dissolved in each liter of solution you must divide the total micromoles of solute by the number of liters of solution.

Here's that idea written as a formula: c= n/V

where c stands for concentration, n stands for the total micromoles of copper (II) sulfate and V stands for the total volume of the solution.

You're not given the volume of the solution in liters, but rather in milliliters. You can convert milliliters to liters with a unit ratio: V= 150. mL * 10^-3 L/ 1 mL = 0.150 L

Next, plug in μmol and liters into the formula to divide the total micromoles of solute by the number of liters of solution: c= 31 μmol/0.150 L = 206.66 μmol/L

Convert this number into scientific notation: 2.06 * 10^2 μmol/L or 2.06 * 10^2 μM

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The coordination sphere of a complex consists of ________. The coordination sphere of a complex consists of ________. the ligand
sammy [17]

Answer:

The coordination sphere of a complex consists of <u><em>the central metal ion and the ligands bonded to it.</em></u>

Explanation:

The Coordination Compounds are sets of a central metal ion attached to a group of molecules or ions that surround it. They are also called metal complexes or simply complexes. Then they are compounds that have a central atom surrounded by a group of molecules or ions, the latter called ligands.

The central atom must have empty orbitals capable of accepting pairs of electrons, with the transition metals being the ones with the greatest tendency. Because of this, they can act as Lewis acids (electron pair acceptors). The ligands have unshared electron pairs, then acting as Lewis bases (electron pair donors).

When forming a complex, it is said that the ligands coordinate to the metal and the central metal and the ligands attached to it constitute the coordination sphere of the complex.

Finally, <u><em>the coordination sphere of a complex consists of the central metal ion and the ligands bonded to it.</em></u>

5 0
3 years ago
A reaction rate increases by a factor of 655 in the presence of a catalyst at 37°C. The activation energy of the original pathwa
irinina [24]

For a reaction rate that increases by a factor of 655 in the presence of a catalyst at 37°C, the activation energy of the new pathway  is mathematically given as

Ea2=89.28JKoule/mol

<h3>What is the activation energy of the new pathway, all other factors being equal?</h3>

Generally, the equation for the rate constant  is mathematically given as

K=Ae^{Ea1/Rt}

Therefore

\frac{1}{655}=\frac{1}{8.31*3.10}(Ea2-105000)

Ea2=89286.083Joule/mol

In conclusion, the activation energy

Ea2=89.28JKoule/mol

Read more about Energy

brainly.com/question/13439286

5 0
3 years ago
What is the half-life of a radioisotope if a 50-g sample becomes 25 g after 18
vredina [299]

Answer:

18 DAYS IS THE HALF LIFE OF THE RADIOISOTOPE.

Explanation:

Using the formula

Nt = No * (1/2)^t/t1/2

where;

Nt = amount remaining = 25 g

No = Initial amounrt of the radioisotope = 50 g

t = time elapsed = 18 days

t1/2 = half life = unknown

Substitute the values into the equation and obtain the half life of the radioisotope;

Nt = No * (1/2) ^t/t1/2

25 = 50 * (1/2) ^18/t1/2

25 /50 =  (1/2)^18/ t1/2

1/2 = (1/2)^18/t1/2

1/2)^1 = (1/2)^18/t1/2

1 = 18/t1/2

t1/2 = 18 days.

So therefore the half life of the radioisotope is 18 days.

4 0
3 years ago
Which particle contains the greatest number of electrons?<br> 1. Na<br> 2. Na+<br> 3. F<br> 4. F-
barxatty [35]

Answer:

Na

Explanation:

The atomic number of sodium is 11 while that of fluorine is 9 . Thus the number of electrons in sodium are 11 while in fluorine are 9 .

The cation of an atom form when atom lose electron.

Na → Na⁺ + e⁻

it means the cation of sodium loses its one outer most electron. Thus it has 10 electron while Na atom has 11 electron.

On other hand fluorine has  9 electrons.

The anion of an atom form when it gain electron.

F + e⁻     →    F⁻

Thus the number of electrons in given species are,

Na = 11

Na⁺ = 10

F = 9

F⁻ = 10

Na has more number of electrons.

5 0
3 years ago
How has everyone been and nice to meet whoever else get's on here.
jeka57 [31]

Answer:

Hello everyone and thnx for points

Explanation:

6 0
3 years ago
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