All categories

3 years ago

Cause and Effect: What would happen to a space vehicle in orbit around Earth if it sped up?

Physics

1 answer:

gulaghasi [49]3 years ago

4 0

Answer:

G M m / R^2 = m v^2 / R gravitational force = centripetal force

G M = v^2 R = constant

As v increases R will must decrease

Take the moon as an example

S = 2 pi R where R is about 240,000 miles for one orbit

S / 1 day = 54,000 miles/day for a 28 day circuit

S / 1 hr = 54000 / 24 = 2200 mph which is much less than a satellite in orbit

You might be interested in

Claire just purchased a new silk dress for her school’s winter formal. She loves the feel of silk and keeps rubbing it with her

bezimeni [28]

Answer:

would adapt if the dress were held completely still

Explanation:

3 0

3 years ago

Read 2 more answers

Which best describes internet wikis as a source of scientific information

scoundrel [369]

Answer:

They are written or edited by anyone

Explanation:

5 0

3 years ago

The gas in a balloon has T=280 K and V=0.0279 m^3. if the temperature increases to 320 K at constant pressure, what is the new v

victus00 [196]

Answer:

0.0319 m³

Explanation:

Use ideal gas law:

PV = nRT

where P is pressure, V is volume, n is amount of gas, R is the gas constant, and T is temperature.

Since P, n, and R are held constant:

n₁ R / P₁ = n₂ R₂ / P₂

Which means:

V₁ / T₁ = V₂ / T₂

Plugging in:

0.0279 m³ / 280 K = V / 320 K

V = 0.0319 m³

8 0

3 years ago

A 15 kg kangaroo jumps with an upward acceleration of 3 m/s2 by pushing hard off the ground.

patriot [66]

Explanation:

The net force would be upwards since the kangaroo would have to overcome gravity to jump

3 0

3 years ago

Read 2 more answers

The magnitude of electrical force between a pair of charged particles is ____ as much when the particles are moved half as far a

Gnesinka [82]

The magnitude of the electrical force between a pair of charged particles is 4 Times as much when the particles are moved half as far apart.

This can be easily understood by Columb's law,

$F_{new} = \frac{kQ_{1}Q_{2}}{r^{2}}$

which state's that the amount of electrical force experienced by two charged particles is inversely proportional to the square of the distance between them.

∴ $\frac{F_{new} }{F_{old} } = \frac{Distance_{new}^{2} }{Distance_{old}^{2} }$

Now, we know the new distance is half the original distance,

$F_{new} = \frac{kQ_{1}Q_{2}}{\frac{r}{2}^{2} } \\F_{new} = 4\frac{kQ_{1}Q_{2}}{r^{2}}$

$F_{new} = 4F_{old}$

The electrical force of attraction or electrostatic force of attraction between two charged particles refers to the amount of attractive or repulsive force that exists between the two charges. This can be calculated by Columb's Law.

A charged particle in physics is a particle that has an electric charge. It might be an ion, such as a molecule or atom having an excess or shortage of electrons in comparison to protons. The same charge is thought to be shared by an electron, a proton, or another primary particle.

Learn more about electrical force here

brainly.com/question/2526815

#SPJ4

8 0

2 years ago