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3 years ago

Cause and Effect: What would happen to a space vehicle in orbit around Earth if it sped up?

Physics

1 answer:

gulaghasi [49]3 years ago

4 0

Answer:

G M m / R^2 = m v^2 / R gravitational force = centripetal force

G M = v^2 R = constant

As v increases R will must decrease

Take the moon as an example

S = 2 pi R where R is about 240,000 miles for one orbit

S / 1 day = 54,000 miles/day for a 28 day circuit

S / 1 hr = 54000 / 24 = 2200 mph which is much less than a satellite in orbit

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Find the voltage across the 15 Q resistor.<br> [?] V<br><br> No links please

Margaret [11]

Answer:

Explanation:

same idea as before Liam, first, find the parallel resistance in 35 || 20

(35*20) / (35+20) = 700 / 55 = 12.727272 ohms

now add the 12.727272 + 15 = 27.727272 ohms total resistance

V = IR

10 = I * 27.727272

10 / 27.727272 = I

0.360655 = I

V = IR (again, but across the 15 ohm resistor)

V = 0.360655 * 15

V = 5.4098

4 0

3 years ago

An amusement park ride consists of a large vertical cylinder that spins about its axis fast enough that a person inside is stuck

ElenaW [278]

Let N be the normal force that forces the person against the wall.

Then u N = m g is the frictional force supporting the person's weight

and N = m g / u

also, N = m v^2 / R is the normal force providing the centripetal acceleration

So, m g / u = m v^2 / R

v^2 = g R / u

since v = 2 pi R T

4 pi^2 R^2 T^2 = g R / u and T^2 = g / (4 u pi^2 R)

T = 1/ (2 pi) (g /(u R))^1/2 = .159 * (9.8 m/s^2 / (.521 * 4.4 m)) ^1/2

T = .68 / s

Do you see any thing wrong here?

T should have units of seconds not 1 / seconds

v should be 2 * pi * R / T where T is the time for 1 revolution

So you need to make that correction in the above formula for v.

7 0

3 years ago

Using a horizontal force of 60 N, a wagon is pushed horizontally across the floor a distance of 12 meters at a constant speed of

RideAnS [48]

Answer:

a) The work done by the force is 720 joules, b) The power supplied by the force is 138 watts.

Explanation:

a) Since force is uniform and parallel to the direction of motion, the work ( $W$ ), in joules, done by the force ( $F$ ), in newtons, is defined by this formula:

$W = F\cdot s$ (1)

Where $s$ is the travelled distance, in meters.

If we know that $F = 60\,N$ and $s = 12\,m$ , then the work done by the force is:

$W = F\cdot s$

$W = (60\,N)\cdot (12\,m)$

$W = 720\,J$

The work done by the force is 720 joules.

b) And an expression for the power supplied by the force ( $\dot W$ ), in watts, is concieved by differentiating (1) in time:

$\dot W = F\cdot \dot s$

Where $\dot s$ is the speed of the wagon, in meters per second.

If we know that $F = 60\,N$ and $\dot s = 2.3\,\frac{m}{s}$ , then the power supplied by the force is:

$\dot W = F\cdot \dot s$

$\dot W = (60\,N)\cdot \left(2.3\,\frac{m}{s} \right)$

$\dot W = 138\,W$

The power supplied by the force is 138 watts.

3 0

3 years ago

Molecules at room temperature move freely. What happens to the molecules when heat is removed until it freezes?

QveST [7]

molecules group together

3 0

3 years ago

Electromagnetic waves, which include light, consist of vibrations of electric and magnetic fields, and they all travel at the sp

Alekssandra [29.7K]

Answer:

2.92682 m

$1.5\times 10^{18}\ Hz$

250000000000 Hz

$2.88462\times 10^{-8}\ m$

0.21126 m

0.12244 m

Explanation:

c = Speed of light = $3\times 10^8\ m/s$

$\lambda$ = Wavelength

f = Frequency

Wavelength is given by

$\lambda=\dfrac{c}{f}\\\Rightarrow \lambda=\dfrac{3\times 10^8}{102.5\times 10^6}\\\Rightarrow \lambda=2.92682\ m$

The wavelength is 2.92682 m

Frequency is given by

$f=\dfrac{c}{\lambda}\\\Rightarrow f=\dfrac{3\times 10^8}{0.2\times 10^{-9}}\\\Rightarrow f=1.5\times 10^{18}\ Hz$

The frequency is $1.5\times 10^{18}\ Hz$

$f=\dfrac{c}{\lambda}\\\Rightarrow f=\dfrac{3\times 10^8}{1.2\times 10^{-3}}\\\Rightarrow f=250000000000\ Hz$

The frequency is 250000000000 Hz

$\lambda=\dfrac{c}{f}\\\Rightarrow \lambda=\dfrac{3\times 10^8}{1.04\times 10^{16}}\\\Rightarrow \lambda=2.88462\times 10^{-8}\ m$

The wavelength is $2.88462\times 10^{-8}\ m$

$\lambda=\dfrac{c}{f}\\\Rightarrow \lambda=\dfrac{3\times 10^8}{1.42\times 10^{9}}\\\Rightarrow \lambda=0.21126\ m$

The wavelength is 0.21126 m

$\lambda=\dfrac{c}{f}\\\Rightarrow \lambda=\dfrac{3\times 10^8}{2.45\times 10^9}\\\Rightarrow \lambda=0.12244\ m$

The wavelength is 0.12244 m

8 0

3 years ago