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3 years ago

The elementary charge equals 1.6 x 10^-9 C. a. True b. False

Physics

1 answer:

yanalaym [24]3 years ago

5 0

Answer:

False

Explanation:

The magnitude of electric charge carried by an electron as well as proton is called elementary charge. Both the electron and proton have the same charge but the difference is that the electrons are negatively charged species and the protons are positively charged.

The elementary charge is equal to $1.6\times 10^{-19}\ C$ . Hence, the given statement "The elementary charge equals $1.6\times 10^{-9}\ C$ " is false.

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According to the law of conservation of energy, which statement must be

alina1380 [7]

Answer: THE ANSWER IS C!

The total energy of a system can decrease only if energy leaves the system.

Explanation: Apex!

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3 years ago

When the play button is pressed, a CD accelerates uniformly from rest to 450 rev/min in 3.0 revolutions. If the CD has a radius

Marina CMI [18]

To solve this problem it is necessary to apply the kinematic equations of angular motion.

Torque from the rotational movement is defined as

$\tau = I\alpha$

where

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The angular acceleration at the same time can be defined as function of angular velocity and angular displacement (Without considering time) through the expression:

$2 \alpha \theta = \omega_f^2-\omega_i^2$

Where

$\omega_{f,i} =$ Final and Initial Angular velocity

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$\theta =$ Angular displacement

Our values are given as

$\omega_i = 0 rad/s$

$\omega_f = 450rev/min (\frac{1min}{60s})(\frac{2\pi rad}{1rev})$

$\omega_f = 47.12rad/s$

$\theta = 3 rev (\frac{2\pi rad}{1rev}) \rightarrow 6\pi rad$

$r = 7cm = 7*10^{-2}m$

$m = 17g = 17*10^{-3}kg$

Using the expression of angular acceleration we can find the to then find the torque, that is,

$2\alpha\theta=\omega_f^2-\omega_i^2$

$\alpha=\frac{\omega_f^2-\omega_i^2}{2\theta}$

$\alpha = \frac{47.12^2-0^2}{2*6\pi}$

$\alpha = 58.89rad/s^2$

With the expression of the acceleration found it is now necessary to replace it on the torque equation and the respective moment of inertia for the disk, so

$\tau = I\alpha$

$\tau = (\frac{1}{2}mr^2)\alpha$

$\tau = (\frac{1}{2}(17*10^{-3})(7*10^{-2})^2)(58.89)$

$\tau = 0.00245N\cdot m \approx 2.45*10^{-3}N\cdot m$

Therefore the torque exerted on it is $2.45*10^{-3}N\cdot m$

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3 years ago

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Wewaii [24]

It is because the potential energy is similar to MgH.

When it comes to MgH, it means mass, gravity and height respectively.

By using the value of acceleration, seema will find the potential energy of a ball.

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4 years ago

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Which of the following is considered to be a vector?

AVprozaik [17]

Answer: B) Velocity

Explanation:

Velocity is a vector quantity. Velocities have both magnitude and direction.

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3 years ago

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ElenaW [278]

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