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3 years ago

The elementary charge equals 1.6 x 10^-9 C. a. True b. False

Physics

1 answer:

yanalaym [24]3 years ago

5 0

Answer:

False

Explanation:

The magnitude of electric charge carried by an electron as well as proton is called elementary charge. Both the electron and proton have the same charge but the difference is that the electrons are negatively charged species and the protons are positively charged.

The elementary charge is equal to $1.6\times 10^{-19}\ C$ . Hence, the given statement "The elementary charge equals $1.6\times 10^{-9}\ C$ " is false.

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A car drives over a hilltop that has a radius of curvature 0.120 km at the top of the hill. At what speed would the car be trave

Mashutka [201]

Answer:

34.3 m/s

Explanation:

Newton's Second Law states that the resultant of the forces acting on the car is equal to the product between the mass of the car, m, and the centripetal acceleration $a_c$ (because the car is moving of circular motion). So at the top of the hill the equation of the forces is:

$mg-R = m a_c = m\frac{v^2}{r}$

where

(mg) is the weight of the car (downward), with m being the car's mass and g=9.8 m/s^2 is the acceleration due to gravity

R is the normal reaction exerted by the road on the car (upward, so with negative sign)

v is the speed of the car

r = 0.120 km = 120 m is the radius of the curve

The problem is asking for the speed that the car would have when it tires just barely lose contact with the road: this means requiring that the normal reaction is zero, R=0. Substituting into the equation and solving for v, we find:

$v=\sqrt{gr}=\sqrt{(9.8 m/s^2)(120 m)}=34.3 m/s$

6 0

3 years ago

A metal ring 4.60 cm in diameter is placed between the north and south poles of large magnets with the plane of its area perpend

telo118 [61]

Answer:

A. Ein = 8.05*10^-4 V/m

B. Clockwise sense

Explanation:

A. the magnitude of the electric field induced in the ring is obtaind by using the following formula:

$\int E_{in} \cdot ds=-\frac{d\Phi_B}{dt}$ (1)

Ein: induced electric field

ds: differential of a path of the ring

ФB: magnetic flux in the ring

The Ein vector is parallel to ds in the complete ring. Furthermore, the area of the ring is constant, hence, you have in the equation (1):

$\int E_{in}ds=E_{in}(2\pi r)=-A\frac{dB}{dt}\\\\E_{in}=-\frac{A}{2\pi r}\frac{dB}{dt}$ (2)

dB/dt = -0.280T/s (it is decreasing)

A: area of the ring = π(r/2)^2= (π/4) r^2

r: radius of the ring = 4.60/2 = 2.30 cm

Then, you replace the values of all variables in the equation (2):

$E_{in}=-\frac{(\pi/4)r^2}{2\pi r}\frac{dB}{dt}=\frac{r}{8}\frac{dB}{dt}\\\\E_{in}=-\frac{0.0230m}{8}(-0.280T)=8.05*10^{-4}\frac{V}{m}$

hence, the induced electric field is 8.05*10^-4 V/m

B. The induced current in the ring produced a magnetic field that is opposite to the magnetic field of the magnet. The, in this case you have that the induced current is in a clockwise sense.

6 0

4 years ago

This physics problem is kinda complicated to my small brains...

Veronika [31]

Answer:

$\huge\boxed{\sf P.E. = 14700\ Joules}$

Explanation:

This work done is in the form of Potential Energy so we'll use the formula of Potential Energy.

<u>Given Data:</u>

Mass = m = 250 kg

Acceleration due to gravity = g = 9.8 m/s²

Height = h = 6 m

<u>Required:</u>

Work Done in the form of Potential Energy = P.E. = ?

<u>Formula:</u>

P.E. = mgh

<u>Solution:</u>

P.E. = (250)(9.8)(6)

P.E. = 14700 Joules

$\rule[225]{225}{2}$

Hope this helped!

4 0

3 years ago

how is a pure substance different from a mixture? A. mixtures can be separated by physical means B. Pure substances are made up

Nataliya [291]

Well, a pure substance Is something that isn't mixed with anything else. it is it's own thing, and a mixture can be separated by physical means, so it is A.

3 0

4 years ago

Give the abbreviation for the unit which is equivalent to (kgm)/s2.

nata0808 [166]

Only units of the SI and those units recognized for use with the SI are used to express the values of quantities. Equivalent values in other units are given in parentheses following values in acceptable units only when deemed necessary for the intended audience.

6 0

3 years ago