Answer:
a.
b.
Explanation:
The frequency of a harmonic oscillator is given by the following formula:
----------------- equation (1)
a.
In order to double the frequency of this oscillator:
ω' = 2ω
m' = ?
Therefore,
using equation (1):
a.
In order to triple the frequency of this oscillator:
ω' = 3ω
m' = ?
Therefore,
using equation (1):
Answer:
) the uniform disk has a lower moment of inertia and arrives first.
Explanation:
(a) the uniform disk has a lower moment of inertia and arrives first.
(b) Let's say the disk has mass m and radius r, and
the hoop has mass M and radius R.
disk: initial E = PE = mgh
I = ½mr², so KE = ½mv² + ½Iω² = ½mv² + ½(½mr²)(v/r)² = (3/4)mv² = mgh
m cancels, leaving v² = 4gh / 3
hoop: initial E = Mgh
I = MR², so KE = ½MV² + ½(MR²)(V/R)² = MV² = Mgh
M cancels, leaving V² = gh
Vdisk = √(4gh/3) > Vhoop = √(gh)
Answer:
40 J
Explanation:
In the case of a rectilinear movement, the work is calculated as the product of Force (N) * movement (m). In your case, unless the angle between the force vector and the displacement vector is different from 0, the work is:
20 N * 2 m = 40 J
Complete Question
A 100-W (watt) light bulb has resistance R=143Ω (ohms) when attached to household current, where voltage varies as V=V0sin(2πft), where V0=110 V, f=60 Hz. The power supplied to the bulb is P=V2R J/s (joules per second) and the total energy expended over a time period [0,T] (in seconds) is
Compute U if the bulb remains on for 5h
Answer:
The value is
Explanation:
From the question we are told that
The power rating of the bulb is
The resistance is
The voltage is
The energy expanded is
The voltage
The frequency is
The time considered is
Generally power is mathematically represented as
=>
=>
So
=>
=>
=>
=>
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