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MAXImum [283]
2 years ago
15

The table below shows the speed of sound waves from musical sound sources at 20°C. Which conclusion can be made based on the inf

ormation in the table? Wave speed and wavelengths can vary inversely to produce the same frequency. Frequency and wave speed can vary directly to produce the same wavelength. Wavelengths and frequency can vary inversely to produce the same wave speed. Frequency and wavelengths can vary directly to produce the same wave speed. Mark this and return
Physics
2 answers:
slamgirl [31]2 years ago
7 0

Answer:

c

Explanation:

KatRina [158]2 years ago
6 0

Answer:

C

Explanation:

Took it on edg

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A 50.0-kg box is being pulled along a horizontal surface by means of a rope that exerts a force of 250 n at an angle of 32.0° ab
Phoenix [80]
According to Newton's second law, the resultant of the forces acting on the box is equal to the product between its mass and its acceleration:
\sum F = ma (1)

we are only concerned about the horizontal direction, so there are only two forces acting on the box in this direction:
- the horizontal component of the force exerted by the rope, which is equal to
F_x = F cos \theta = (250N)(\cos 32.0^{\circ} )=212.0 N
- the frictional force, acting in the opposite direction, which is equal to
F_f = \mu mg=(0.350)(50.0 kg)(9.81 m/s^2)=171.7 N

By applying Newton's law (1), we can calculate the acceleration of the box:
F_x - F_f = ma
a= \frac{F_x - F_f}{m}= \frac{212.0 N-171.7 N}{50.0 kg} =0.81 m/s^2

6 0
3 years ago
You, a 70 kg person, leap from a 10 m tall building and land feet first on a trampoline. The center of the trampoline where you
Anon25 [30]

Answer:

1373.4 N/m

Explanation:

Hooke's law states that the extension of a spring and force are related by the expression, F=kx where k is spring constant, x is extension of spring and F is the applied force. Making k the subject of the formula then

k=\frac {F}{x}

Also, F=gm hence the above formula is modified as

k=\frac {gm}{x}

Taking g as 9.81 m/s2 , x as 0.5 m and m as 70 kg then

k=\frac {9.81\times 70 kg}{0.5m}=1373.4 N/m

4 0
3 years ago
A mass of 148 g stretches a spring 13 cm. The mass is set in motion from its equlibrium position with a downward velocity of 10
Charra [1.4K]

Answer:

u(t)=1.15 \sin (8.68t)cm

0.3619sec

Explanation:

Given that

Mass,m=148 g

Length,L=13 cm

Velocity,u'(0)=10 cm/s

We have to find the position u of the mass at any time t

We know that

\omega_0=\sqrt{\frac{g}{L}}\\\\=\sqrt{\frac{980}{13}}\\\\=8.68 rad/s

Where g=980 cm/s^2

u(t)=Acos8.68 t+Bsin 8.68t

u(0)=0

Substitute the value

A=0\\u'(t)=-8.68Asin8.68t+8.68 Bcos8.86 t

Substitute u'(0)=10

8.68B=10

B=\frac{10}{8.68}=1.15

Substitute the values

u(t)=1.15 \sin (8.68t)cm

Period =T = 2π/8.68

After half period

π/8.68 it returns to equilibruim

π/8.68 = 0.3619sec

6 0
3 years ago
A grasshopper leaps into the air at a 62° angle above the horizontal, and follows a parabolic arc in free fall after it leaves t
harina [27]

Answer:

d. None of the above.

Explanation:

In a parabolic motion, you have that in the complete trajectory the component velocity is constant and the vertical component changes in time. Then, the total velocity vector is not zero.

In the complete trajectory the gravitational acceleration is always present. Then, the grasshopper's acceleration vector is not zero.

At the top of the arc the grasshopper is not at equilibrium because the gravitational force is constantly acting on the grasshopper.

Then, the correct answer is:

d. None of the above.

5 0
3 years ago
find the resistance of a resistor connected to a 3v voltmeter and a 3A ammeter, resistance box along with cells of EMF 3V​
yarga [219]

Answer:

0

Explanation:

Emf E= V+ terminal V

3 = 3R + 3

R=0

5 0
3 years ago
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