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MAXImum [283]
3 years ago
15

The table below shows the speed of sound waves from musical sound sources at 20°C. Which conclusion can be made based on the inf

ormation in the table? Wave speed and wavelengths can vary inversely to produce the same frequency. Frequency and wave speed can vary directly to produce the same wavelength. Wavelengths and frequency can vary inversely to produce the same wave speed. Frequency and wavelengths can vary directly to produce the same wave speed. Mark this and return
Physics
2 answers:
slamgirl [31]3 years ago
7 0

Answer:

c

Explanation:

KatRina [158]3 years ago
6 0

Answer:

C

Explanation:

Took it on edg

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These capacitors are then disconnected from their batteries, and the positive plates are now connected to each other and the neg
Kay [80]

Answer:

Following are the solution to the given question:

Explanation:

For charging plates that are connected in a similar manner:

Calculating the total charge:

\to q =q_1 + q_2 = C_1V_1 +C_2V_2 =1320 + 2714 = 4034 \mu C

Calculating the common potential:

\to V = \frac{q}{C}= \frac{q}{(C_1 + C_2)} =\frac{4034}{6.8} = 593 \ V\\\\

Calculating the charge after redistribution:

When: \\\\q = q_{1}' + q_{2}' = q_1 + q_2        

\to q_{1}' = C_1V = 2.2 \times 593 = 1305\ \mu C\\  \\  \to               q_{2}' = C_2V = 4.6 \times 593 = 2729 \ \mu C

6 0
3 years ago
Can someone please help me get this right pleaseee I’ll mark brainless .
Katarina [22]

Answer:i think it is c

Explanation:

4 0
3 years ago
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If you are driving your car at 45.0 miles per hour, and you have been driving 2.50 hours, how far has your car gone?
Greeley [361]

Answer:

113 miles

Explanation:

45.00 x 2.50= 1.12.5 so 113 miles in 2.50 hours

5 0
3 years ago
How many meters will a person run during a 5-mile race
Rashid [163]

Answer:

8046.72 meters pretty sure

8 0
3 years ago
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At a certain instant an object is moving to the right with speed 1.0 m/s and has a constant acceleration to the left of 1.0 m/s2
professor190 [17]

Explanation:

Given that,

Initial speed of the object, u = 1 m/s

Acceleration of the object, a=-1\ m/s^2

We need to find the time when the object comes at rest (v=0). Let it is given by :

t=\dfrac{v-u}{a}

t=\dfrac{0-1\ m/s}{-1\ m/s^2}

t = 1 second

So, the object will comes to rest at 1 second. Hence, this is the required solution.

5 0
3 years ago
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