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MAXImum [283]
3 years ago
15

The table below shows the speed of sound waves from musical sound sources at 20°C. Which conclusion can be made based on the inf

ormation in the table? Wave speed and wavelengths can vary inversely to produce the same frequency. Frequency and wave speed can vary directly to produce the same wavelength. Wavelengths and frequency can vary inversely to produce the same wave speed. Frequency and wavelengths can vary directly to produce the same wave speed. Mark this and return
Physics
2 answers:
slamgirl [31]3 years ago
7 0

Answer:

c

Explanation:

KatRina [158]3 years ago
6 0

Answer:

C

Explanation:

Took it on edg

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A classroom has 24 fluorescent bulbs, each of which is 32 W. how much energy does it take to light the room for a minute?(unit=J
cestrela7 [59]

Answer:

Energy= 46.08KJ

Explanation:

Given that the power needed to light each bulb is 32W

We know that Power = \frac{energy}{time}

The energy needed to light one bulb=power*time

Given time = 1minute = 60 seconds

Energy = 32W*60sec=1920J

Therefore energy needed to light one bulb is 1920J

The energy needed to light 24 bulbs = 1920*24 =46080J=46.08KJ

3 0
3 years ago
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fomenos

Answer:

1 hr 45 min

Explanation:

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A book is to be produced with pages of thickness 0.125mm.If the book is to be exactly 1cm thick what is the maximum number of pa
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1cm=10mm

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3 years ago
An asteroid orbiting the Sun has a mass of 4.00×1016 kg. At a particular instant, it experiences a gravitational force of 3.14×1
Ksivusya [100]
<h2>The asteroid is 4.11 x 10¹¹ m far from Sun</h2>

Explanation:

We have gravitational force

                 F=\frac{GMm}{r^2}

           Where G =  6.67 x 10⁻¹¹ N m²/kg²

                       M = Mass of body 1

                       M = Mass of body 2

                       r = Distance between them

Here we have

                 M = Mass of Sun = 1.99×10³⁰ kg

                 m = Mass of asteroid = 4.00×10¹⁶ kg

                 F = 3.14×10¹³ N

Substituting

                   F=\frac{GMm}{r^2}\\\\3.14\times 10^{13}=\frac{6.67\times 10^{-11}\times 1.99\times 10^{30}\times 4\times 10^{16}}{r^2}\\\\r=4.11\times 10^{11}m

The asteroid is 4.11 x 10¹¹ m far from Sun

3 0
3 years ago
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