I think its the sun not 100% sure...
Answer:
78 percent
Explanation:
I guess that's the right answer
Answer:
force exert horizontally is 1 N
Explanation:
given data
bar length = 3.7 m
mass = 4.5 kg
rope length = 6.7 m
to find out
force exert horizontally
solution
we know here bar length and rope length that make angle θ
so here cos θ = (3.7/6.7)
so equating the torque here to find force in horizontal direction is
Fx = T cos θ .........1
and in vertical direction
Tsinθ + N = mg .............2
so here
we consider equilibrium condition
so
Fx = 0
T cos θ = 0
T 3.7 / 6.7 = 0
T = 6.7/3.7
T = 1.81
so from equation 1
Fx = T cosθ
Fx = 1.81 ( 3.7/6.7)
Fx = 1 N
so force exert horizontally is 1 N
Answer:
16.9000000000000001 J
Explanation:
From the given information:
Let the initial kinetic energy from point A be 
= 1.9000000000000001 J
and the final kinetic energy from point B be 
= ???
The charge particle Q = 6 mC = 6 × 10⁻³ C
The change in the electric potential from point B to A;
i.e. V_B - V_A = -2.5 × 10³ V
According to the work-energy theorem:
-Q × ΔV = ΔK
So i think that the question you are asking is the one of the exercise that says that the rope is very short and throws his bag also and you need to find the final speed of the bag tools. Well given the data we can use this next formulas to do this. First we are talking about conserve momentum: So we use a formula with the data like this:
<span>(135 + 13.0)kg * 1.50m/s = 135kg * V + 13.0kg * v </span>
<span>As we want V = 0; then </span>
<span>minimum v = 148kg * 1.50m/s / 13.0kg = 17.1 m/s
I hope is what you were looking for </span>
