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TEA [102]
3 years ago
14

Which of the following statements are true for magnetic force acting on a current-carrying wire in a uniform magnetic field? Che

ck all that apply. Check all that apply. The magnetic force on the current-carrying wire is strongest when the current is perpendicular to the magnetic field lines. The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the field. The magnetic force on the current-carrying wire is strongest when the current is parallel to the magnetic field lines. The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the current.
Physics
1 answer:
qaws [65]3 years ago
6 0

Answer:

The following statements are correct.

1. The magnetic force on the current-carrying wire is strongest when the current is perpendicular to the magnetic field lines.

2. The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the field.

3. The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the current.

Wrong statements:

1. The magnetic force on the current-carrying wire is strongest when the current is parallel to the magnetic field lines.

Explanation:

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When the speed of your car is doubled, by what factor does its kinetic energy increase?
Tju [1.3M]

Answer:

a. 4

Explanation:

Hi there!

The equation of kinetic energy (KE) is the following:

KE = 1/2 · m · v²

Where:

m = mass of the car.

v = speed of the car.

Let´s see how would be the equation if the velocity is doubled (2 · v)

KE2 = 1/2 · m · (2 · v)²

Distributing the exponent:

KE2 = 1/2 · m · 2² · v²

KE2 = 1/2 · m · 4 · v²

KE2 = 4 (1/2 · m · v²)      

KE2 = 4KE

Doubling the velocity increased the kinetic energy by 4.

7 0
3 years ago
a body initially at rest, starts moving with a constant acceleration of 2ms-2 .calculate the velocity acquired and the distance
Marta_Voda [28]

a) 10 m/s

b) 25 m

Explanation:

a)

The body is moving with a constant acceleration, therefore we can solve the problem by using the following suvat equation:

v=u+at

where

u is the initial velocity

v is the final velocity

a is the acceleration

t is the time

For the body in this problem:

u = 0 (the body starts from rest)

a=2 m/s^2 is the acceleration

t = 5 s is the time

So, the final velocity is

v=0+(2)(5)=10 m/s

b)

In this second part, we want to calculate the distance travelled by the body.

We can do it by using another suvat equation:

v^2-u^2=2as

where

u is the initial velocity

v is the final velocity

a is the acceleration

s is the distance travelled

Here we have

u = 0 (the body starts from rest)

a=2 m/s^2 is the acceleration

v = 10 m/s is the final velocity

Solving for s,

s=\frac{10^2-0^2}{2(2)}=25 m

3 0
3 years ago
The height a ball bounces is less than the height of the previous bounce due to friction. The heights of the bounces form a geom
AlladinOne [14]

Answer:

Explanation:

Let the first height be h . second height .75h

third height .75h . fourth height .75²h

fifth height .75²h , sixthth height .75³ and so on

Total distance consists of two geometric series as follows

1 ) first series

h + .75h + .75²h + .75³h......

2 )  second series

.75h +.75²h +.75³h + .75⁴h .......

Sum of first series :

first term a = h , commom ratio r = .75

sum = a / (1 - r )

= h / 1 - .75

= h / .25

4h

sum of second series :--

first term a = .75 h , commom ratio r = .75

sum = a / (1 - r )

= .75h / 1 - .75

= .75h / .25

3h

Total of both the series

= 4h + 3h

= 7h .

h = 1 m

Total distance = 7 m

6 0
3 years ago
Which of the following is a FALSE statement about acceleration? A. Acceleration can be zero, positive, or negative. B. An object
olchik [2.2K]
<h3><u>Answer</u>;</h3>

C. An object can have acceleration with negative velocity.

<h3><u>Explanation</u>;</h3>
  • Acceleration is a measure of the change in velocity over time. The change in velocity is measured in meter per second (m/s), and time interval is measured in second (s).
  • Therefore, acceleration measures the change in meters per second every second [(m/s)/s], namely meters per second per second or meters per second squared (m/s2).
  • If an object has zero acceleration, its velocity doesn’t have to be zero. Acceleration is a measure of the change in velocity over time. Zero acceleration means there is no change in velocity over time, namely constant velocity.
6 0
3 years ago
A vehicle accelerates from 0 to 30 m/s in 10 seconds on a straight road
Solnce55 [7]
What's the question?

6 0
2 years ago
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