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2 years ago

True or false? different reactions require different catalysts.

Chemistry

1 answer:

lapo4ka [179]2 years ago

8 0

True, different reactions require different catalysts. Hence, option 1 is correct.

<h3>What are catalysts?</h3>

A catalyst is a substance that speeds up a chemical reaction or lowers the temperature or pressure needed to start one, without itself being consumed during the reaction.

Though a catalyst is supposed to remain unaltered at the end of the reaction, it does take part in the reaction by providing active centres for the reaction to take place.

By helping to form a suitable activated complex in the course of the reaction, the catalyst increases the rate of formation of the product, as well as its yield.

Therefore, a catalyst has to be reactant-specific to form the favourable activated complex or intermediate.

Hence, option 1 is correct.

Learn more about the catalysts here:

brainly.com/question/12260131

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combustion analysis of a hydrocarbon produced 33.01g CO2 and 13.51g H2O. Calculate the empirical formula for the hydrocarbon

masya89 [10]

Answer:

$\rm CH_2$ .

Explanation:

Carbon and hydrogen are the only two elements in a hydrocarbon. When a hydrocarbon combusts completely in excess oxygen, the products would be $\rm CO_2$ and $\rm H_2O$ . The $\rm C$ and $\rm H$ would come from the hydrocarbon, while the $\rm O$ atoms would come from oxygen.

Look up the relative atomic mass of these three elements on a modern periodic table:

$\rm C$ : $12.011$ .
$\rm H$ : $1.008$ .
$\rm O$ : $\rm 15.999$ .

Calculate the molar mass of $\rm CO_2$ and $\rm H_2O$ :

$M(\mathrm{CO_2}) = 12.011 + 2 \times 15.999 = 44.009\; \rm g \cdot mol^{-1}$ .

$M(\mathrm{H_2O}) = 2 \times 1.008 + 15.999 = 18.015\; \rm g \cdot mol^{-1}$

Calculate the number of moles of $\rm CO_2$ molecules in $33.01\; \rm g$ of $\rm CO_2\!$ :

$\displaystyle n(\mathrm{CO_2}) = \frac{m(\mathrm{CO_2})}{M(\mathrm{CO2})} = \frac{33.01\; \rm g}{44.009\; \rm g\cdot mol^{-1}} \approx 0.7501\; \rm mol$ .

Similarly, calculate the number of moles of $\rm H_2O$ molecules in $13.51\; \rm g$ of $\rm H_2O\!$ :

$\displaystyle n(\mathrm{H_2O}) = \frac{m(\mathrm{H_2O})}{M(\mathrm{H_2O})} = \frac{13.51\; \rm g}{18.015\; \rm g\cdot mol^{-1}} \approx 0.7499\; \rm mol$ .

Note that there is one carbon atom in every $\rm CO_2$ molecule. Approximately $0.7501\; \rm mol$ of $\rm CO_2\!$ molecules would correspond to the same number of $\rm C$ atoms. That is: $n(\mathrm{C}) \approx 0.7501\; \rm mol$ .

On the other hand, there are two hydrogen atoms in every $\rm H_2O$ molecule. approximately $0.7499\; \rm mol$ of $\rm H_2O$ molecules would correspond to twice as many $\rm H\!$ atoms. That is: $n(\mathrm{H}) \approx 2 \times 0.7499 \; \rm mol\approx 1.500\; \rm mol$ .

The ratio between the two is: $n(\mathrm{C}): n(\mathrm{H}) \approx 1:2$ .

The empirical formula of a compound gives the smallest whole-number ratio between the elements. For this hydrocarbon, the empirical formula would be $\rm CH_2$ .

6 0

3 years ago

Suppose you have a sample of table salt (NaCl) that has a mass of 100.0 grams. If

IgorC [24]

Taking into account the definition of molarity, the concentration of the solution is 0.855 $\frac{moles}{liter}$ .

<h3>Definition of molarity</h3>

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

$Molarity=\frac{number of moles}{volume}$

Molarity is expressed in units $\frac{moles}{liter}$ .

<h3>Molarity of NaCl</h3>

In this case, you have:

number of moles of NaCl= $100 grams\frac{1 mole}{58.45 grams} =$ 1.71 moles (being 58.45 g/mole the molar mass of NaCl)
volume 2 L

Replacing in the definition of molarity:

$Molarity=\frac{1.71 moles}{2 L}$

Solving:

Molarity= 0.855 $\frac{moles}{liter}$

Finally, the concentration of the solution is 0.855 $\frac{moles}{liter}$ .

Learn more about molarity:

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5 0

2 years ago

What astronomical equiptment did hypatia use?

abruzzese [7]

Hypatia used an astrolabe.

8 0

3 years ago

Mr. Gordon's science students are studying scale models of the Sun-Earth-Moon system. Mr. Gordon is using this model to show his

4vir4ik [10]

The sun is too small

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3 years ago

What is the covalent<br> bonding of calcium chloride

algol13

Answer:

<u>Calcium chloride does not have a covalent bond , it is an ionic bond (which means donation of electrons takes place )</u>. The charge of calcium ions is +2, while the charge of sodium ions is -1. The molecule of calcium chloride contains one calcium ion (+2) and two chloride ions (-1), resulting in an overall charge of 0, or neutral.

<u>IONIC BONDING IN CALCIUM CHLORIDE</u> $(CaCl_2)$

Electron sharing produces covalent compounds, while electron donation produces ionic compounds. $CaCl_2$ is a salt with an ionic bond. This is because calcium takes up an electron to each of the chlorine atoms, resulting in $Ca^2^+$ ions for calcium and $Cl^-$ ions for chlorine. At room temperature, it behaves like a normal ionic halide and is solid. Calcium is a metal with a non-metal sulphate bond.

<u>Thus , Calcium chloride have ionic bonds present on them . No covalent bonds takes place in calcium chloride.</u>

5 0

3 years ago