Question

Acetylene, C2H2, can be converted to ethane, C2H6, by a process known as hydrogenation. The reaction is C2H2(g)+2H2(g)?C2H6(g)

Answer 1

Answer:

part A =  K = 2.7*10^42

Part B =  ΔG  = -252284 J = -252.3 kJ

Explanation:

Step 1: Data given

Step 2: The balanced equation

C2H2(g)+2H2(g) ⇄ C2H6(g)

Δ Gf = (1* GfC2H6) - (1*GfC3H2)

Δ Gf = -209.2 -32.89

Δ Gf = - 242.09 kJ/mol  = -242090 J/mol

Step 3 Calculate K

Δ Gf = -RT ln K

⇒Δ Gf = -242090 J/mol

⇒R = 8.314 J/mol*K

⇒T = the temperature = 298 K

⇒ K = the equilibrium constant

-242090 = - (8.314)(298) lnK

K = 2.7*10^42

PArt B:

Δ Gf = -242.1 kJ= -242100 J

Q = pressure products / pressure reactants

Q = (pC2H6) / (pH2² * pC2H2)

Q = 1.25 / (4.45²*3.85)

Q= 0.0164

ΔG = ΔG° + RT ln Q

ΔG  = -242100  + 8.314 * 298 * ln 0.0164

ΔG  = -252284 J = -252.3 kJ

Answer 2

Answer:

Keq =1.50108

Explanation:

The given reactionis

 C₂H₂(g) +2H₂(g) -------------> C₂H₂(g)

   ΔG0 f=ΔG0f n (products) - ΔG0f n (reactants )

              = -32.89 kJ/mol - (209.2 kJ/mol+2*0.0 kJ/mol)

              = - 242.09kJ/mol

   ΔG= -RTlnKeq

   ln Keq = -ΔG/RT

           =-(- 242.09kJ/mol ) / 2 k cal /mol*298 K

           =0.406

    Keq =e0.406

         Keq =1.50108