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tensa zangetsu [6.8K]
3 years ago
11

Acetylene, C2H2, can be converted to ethane, C2H6, by a process known as hydrogenation. The reaction is C2H2(g)+2H2(g)?C2H6(g)

Chemistry
2 answers:
saw5 [17]3 years ago
7 0

Answer:

part A =  K = 2.7*10^42

Part B =  ΔG  = -252284 J = -252.3 kJ

Explanation:

Step 1: Data given

Step 2: The balanced equation

C2H2(g)+2H2(g) ⇄ C2H6(g)

Δ Gf = (1* GfC2H6) - (1*GfC3H2)

Δ Gf = -209.2 -32.89

Δ Gf = - 242.09 kJ/mol  = -242090 J/mol

Step 3 Calculate K

Δ Gf = -RT ln K

⇒Δ Gf = -242090 J/mol

⇒R = 8.314 J/mol*K

⇒T = the temperature = 298 K

⇒ K = the equilibrium constant

-242090 = - (8.314)(298) lnK

K = 2.7*10^42

PArt B:

Δ Gf = -242.1 kJ= -242100 J

Q = pressure products / pressure reactants

Q = (pC2H6) / (pH2² * pC2H2)

Q = 1.25 / (4.45²*3.85)

Q= 0.0164

ΔG = ΔG° + RT ln Q

ΔG  = -242100  + 8.314 * 298 * ln 0.0164

ΔG  = -252284 J = -252.3 kJ

Alecsey [184]3 years ago
3 0

Answer:

Keq =1.50108

Explanation:

The given reactionis

 C₂H₂(g) +2H₂(g) -------------> C₂H₂(g)

   ΔG0 f=ΔG0f n (products) - ΔG0f n (reactants )

              = -32.89 kJ/mol - (209.2 kJ/mol+2*0.0 kJ/mol)

              = - 242.09kJ/mol

   ΔG= -RTlnKeq

   ln Keq = -ΔG/RT

           =-(- 242.09kJ/mol ) / 2 k cal /mol*298 K

           =0.406

    Keq =e0.406

         Keq =1.50108

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3 years ago
The mass of an unidentified rock is 40 grams. Students determine the volume of the rock by placing the rock in a cylinder with w
insens350 [35]

Answer:

A. Coal

Explanation:

Volume_{rock} = water displaced by rock

Water displaced by rock = volume of water after rock is dropped into the cylinder - volume of water before the rock was dropped into the water

Water displaced by the rock = 180 ml - 150 ml = 30 ml

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Density of rock:

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Density of rock = 1.3 g per 1 ml

Recall: 1 ml = 1 cm³

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7 0
3 years ago
The solubility of a gas is 0.890 g/L at a pressure of 120 kPa. What is the solubility of the gas if the pressure is changed to 1
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The solubility of the gas if the pressure is changed to 100 kPa is 0.742 g/L

<h3>Effect of Pressure on Solubility </h3>

As the <em>pressure </em>of a gas increases, the <em>solubility </em>increases, and as the <em>pressure </em>of a gas decreases, the <em>solubility </em>decreases.

Thus, Solubility varies directly with Pressure

If S represents Solubility and P represents Pressure,

Then we can write that

S ∝ P

Introducing proportionality constant, k

S = kP

S/P = k

∴ We can write that

\frac{S_{1} }{P_{1} } = \frac{S_{2} }{P_{2} }

Where S_{1} is the initial solubility

P_{1} is the initial pressure

S_{2} is the final solubility

P_{2} is the final pressure

From the given information

S_{1} = 0.890 \ g/L

P_{1} = 120 \ kPa

P_{2} = 100 \ kPa

Putting the parameters into the formula, we get

\frac{0.890}{120}=\frac{S_{2}}{100}

S_{2}= \frac{0.890 \times 100}{120}

S_{2}= 0.742 \ g/L

Hence, the solubility of the gas if the pressure is changed to 100 kPa is 0.742 g/L

Learn more on Solubility here: brainly.com/question/4529762

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Of the total base sequence in human DNA, what percentage codes for proteins? A) Nearly 50 percent
aliya0001 [1]

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The correct answer is B)About 5 percent

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