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ivolga24 [154]
3 years ago
9

Hi!! please help! i have 20 mins to turn this in!! :))

Chemistry
1 answer:
VikaD [51]3 years ago
4 0
The answer is A buddy boy
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O ar se apresenta no estado gasoso, é uma mistura de gases. A poluição do ar é a introdução de qualquer substância que, devido a
MakcuM [25]

Answer:

poluição atmosférica

Explanation:

O que eles estão tentando falar na pergunta é que a que termo nos referimos como a introdução de partículas estranhas na forma de suspensão etc. na atmosfera.

Este termo é conhecido como poluição do ar. É chamado assim porque, adulteramos a constituição original do ar, introduzindo esses novos componentes.

Esses componentes introduzidos muitas vezes têm um efeito adverso na composição da qualidade do ar.

6 0
4 years ago
A gas has a volume of 13.4 L at 17C. What is the volume of the gas at standard temperature?
VashaNatasha [74]

Answer:

This law states that the volume and temperature of a gas have a direct relationship: As temperature increases, volume increases, when pressure is held constant. Heating a gas increases the kinetic energy of the particles, causing the gas to expand.

Explanation:

6 0
3 years ago
Explain the relationship between heat and<br> thermal energy
stira [4]

Answer:

the explanation between heat and thermal energy is heat and thermal energy both consume the the proverbs which basically means they are the same thing in a way

Explanation:

heat is something that gets hot by the sun and thermal is something that is hot by the sun

3 0
3 years ago
When a sample of a gas is heated in a sealed, rigid container from 200. K to 400. K, the pressure exerted by the gas is
Brilliant_brown [7]
\frac {p_1} {T_1} = \frac {p_2} {T_2} \\ p_1T_2 = p_2T_1 \\ p_1 \cdot 200 = p_2 \cdot 400 ||: 200 \\ p_1 = p_2 \cdot 2 ||: 2 \\ \frac{1}{2} p_1 = p_2<span>
</span>
<u>(1) zmniejszyła się o czynnik 2. </u>
<span>(2) zwiększona o współczynnik 2. </span>
<span>(3) zmniejszona o współczynnik 200. </span>
<span>(4) zwiększona o współczynnik 200.</span>

<u />


5 0
3 years ago
In a laboratory experiment you are given 46.1 grams of MgSO4 and asked to make a 1.20 M solution. The volume of your solution wi
Darina [25.2K]

Answer:

0.319 L

Explanation:

M(MgSO4) = 120 g/mol

46.1 g * 1 mol/120 g = 0.384 mol MgSO4

0.384 mol * 1 L/1.20 mol = 0.319 L

5 0
3 years ago
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