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ivolga24 [154]
3 years ago
9

Hi!! please help! i have 20 mins to turn this in!! :))

Chemistry
1 answer:
VikaD [51]3 years ago
4 0
The answer is A buddy boy
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6. List the following particles in size order, from<br> biggest to smallest?
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Answer:

the particles, molecules, and gas range from smallest to largest in the following order: electron < proton < atom <...

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3 years ago
Consider the following system at equilibrium:A(aq)+B(aq) &lt;---&gt; 2C(aq)Classify each of the following actions by whether it
velikii [3]

Explanation:

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

  • On addition of reactant at equilibrium shifts the equilibrium in forward direction.
  • On addition of product at equilibrium shifts the equilibrium in backward direction.
  • On removal of reactant at equilibrium shifts the equilibrium in backward direction.
  • On removal of product at equilibrium shifts the equilibrium in forward direction.

A(aq)+B(aq)\rightleftharpoons 2C(aq)

Reactants = A , B

Product = C

1. Increase A

On increasing the amount of A at equilibrium will shift the equilibrium in forward or rightward direction.

2. Increase B

On increasing the amount of B at equilibrium will shift the equilibrium in forward or rightward direction.

3. Increase C

On increasing the amount of C at equilibrium will shift the equilibrium in backward or leftward direction.

4. Decease A

On decreasing the amount of A at equilibrium will shift the equilibrium in backward or leftward direction.

5. Decease B

On decreasing the amount of B at equilibrium will shift the equilibrium in backward or leftward direction.

6. Decease C

On decreasing the amount of C at equilibrium will shift the equilibrium in forward or rightward direction.

7. Double A and Halve B

Equilibrium constant of the reaction = K

K=\frac{[C]^2}{[A][B]}

On doubling A and halving B, equilibrium constant of the reaction = K'

K'=\frac{[C]^2}{[2A][\frac{B}{2}]}=\frac{[C]^2}{[A][B]}

The value of equilibrium constant K' is equal to K, which means that equilibrium will not shift in any direction.

8. Double both B and C

Equilibrium constant of the reaction = K

K=\frac{[C]^2}{[A][B]}

On doubling B and C, equilibrium constant of the reaction = K'

K'=\frac{[2C]^2}{[A][2B]}=\frac{4[C]^2}{[A][2B]}=\frac{2[C]^2}{[A][B]}

K' = 2 K

The value of equilibrium constant K' is double the K, which means that product is increasing which means that equilibrium will shift in backward or leftward direction.

5 0
3 years ago
Which of the following is equal to an impulse of 18 units?
dem82 [27]
The answer is force=6, time=3, so C is correct
8 0
3 years ago
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Identify the element below and give the symbols of the other elements in its group. [ar]4s23d104p4 element symbol:
Katyanochek1 [597]
<span>[Ar]4s²3d¹⁰4p⁴

We see that the last level is this element is 4, so this element should be in
4th period, it has 4 p-electrons, so it should be in 16th group.
4th period, 16th group - it is Se.

You can also go to the next element after Ar, and count beginning of this element 16. (2+10+4 =16 electrons)
 From "K" (where K is the first) you count to 16 and it is going to be Se.</span>
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Would it be possible to conduct an UV/Vis spectroscopy experiment on a sample of the compound C3H3O2? Explain.
alexandr402 [8]
Different substances can interact differently with light. So for me, I think the answer would be yes. It is possible <span>to conduct an UV/Vis spectroscopy experiment on a sample of the compound C3H3O2. Every substance is unique and has its own light interactions.</span>
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3 years ago
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